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Alexeev081 [22]
3 years ago
15

What dose (-1/4) * (1/3)=

Mathematics
2 answers:
Nataly [62]3 years ago
4 0

Answer:

7/12

Step-by-step explanation:

ankoles [38]3 years ago
4 0

Answer:

(-\frac{1}{4}) x (\frac{1}{3})

Step-by-step explanation:

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Find the length of the midsegment of the trapezoid.
Triss [41]

Answer:

29

Step-by-step explanation:

The Trapezoid Midsegment segment theorem states that the length of the midsegment is half the sum of the length of its two parallel sides. Therefore:

MN = ½(AB + DC)

MN = ½(21 + 37)

MN = ½(58)

MN = 29

6 0
3 years ago
Given f (x) = 3x – 5 and g(x) = 2x + 1, find g(f(x)). 6x2 – 7x – 5 6x – 10 6x – 2 6x – 9
N76 [4]

Answer:

g(f(x)) = 6x - 9

Step-by-step explanation:

To find g(f(x)), substitute x = f(x) into g(x) , that is

g(3x - 5)

= 2(3x - 5) + 1 ← distribute parenthesis and simplify

= 6x - 10 + 1

= 6x - 9

5 0
3 years ago
Read 2 more answers
The area of a table is 8ft^2 and the length is 4ft. The width of the table top is?
Natalka [10]
The formula for area is A = L*W or we can say A=LW. Lets plugin what we know.

A = LW
8 = 4W
Now solve for W
8 = LW
8=LW
8/4 = 4W / 4
2 = W
W = 2

So the width is 2ft
6 0
4 years ago
Simplify 7/the square root of 2 (as a fraction)
ioda

HERE IS YOUR ANSWER.......

7 0
3 years ago
How to solve for first derivative?? I have two questions, one where I have the answer, however one where I don’t. The format of
rjkz [21]

Answer:

Q1: f'(x) = (-6x^8 + 2x^4 + 4)(48x^7) + (6x^8)(-48x^7 + 8x^3)

Q2: f'(x) = (6x^4)(18x^2 - 54x^8) + (6x^3 - 6x^9 + 3)(24x^3)

Step-by-step explanation:

The derivative of the product of two functions is:

f(x) = v(x)u(x)

f'(x) = v(x)u'(x) + u(x)v'x)

The derivative is the product of the first function and the derivative of the second function added to the product of the second function and the derivative of the first function.

Q1: The function you are given is:

f(x) = 6x^8(-6x^8 + 2x^4 + 4)

You can think of that function as the product of functions

u(x) = 6x^8 and v(x) = -6x^8 + 2x^4 + 4

We first find the derivatives of functions u and v:

u'(x) = 48x^7 and v'(x) = -48x^7 + 8x^3

Now we follow the rule above:

f'(x) = v(x)u'(x) + u(x)v'x)

f'(x) = (6x^8)(-48x^7 + 8x^3) + (-6x^8 + 2x^4 + 4)(48x^7)

Use the commutative property to change the order of the sum.

f'(x) = (-6x^8 + 2x^4 + 4)(48x^7) + (6x^8)(-48x^7 + 8x^3)

This is the solution you have.

Q2: The function you are given is:

f(x) = 6x^4(6x^3 - 6x^9 + 3)

You can think of that function as the product of functions

u(x) = 6x^4 and v(x) = 6x^3 - 6x^9 + 3

We first find the derivatives of functions u and v:

u'(x) = 24x^3 and v'(x) = 18x^2 - 54x^8

Now we follow the rule above:

f'(x) = v(x)u'(x) + u(x)v'x)

f'(x) = (6x^4)(18x^2 - 54x^8) + (6x^3 - 6x^9 + 3)(24x^3)

5 0
3 years ago
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