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irinina [24]
3 years ago
7

What is a real world example of a molecular pump in the human body?

Biology
2 answers:
erik [133]3 years ago
7 0
There are many cells in your body that use pumps to move molecules. For example, your nerve cells (neurons) would not send messages to your brain unless you had protein pumps moving molecules by active transport. The sodium-potassium pump (Figure below) is an example of an active transport pump! Have a nice day
Alja [10]3 years ago
6 0

Answer:

The most common example of a molecular pump in the human body is the pump for sodium and potassium.

Explanation:

Sodium ions and ATP bind to the pump to use energy to change the shape. The sodium then leaves and the potassium can now bind due to the shape change. The potassium ions are then released and the pump goes back to normal for the cycle to repeat again.

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3 years ago
How many grams of the compound in the figure above are required to make 1 liter of a 0.5 M solution? (Note: The atomic masses, i
Dafna1 [17]

Answer:

This question is incomplete as there is no figure in the question but the compound in the figure is Ethanoic acid (CH3COOH). Hence, we can calculate the mass.

The answer is: 30grams

Explanation:

According to the question, the volume of the compound (CH3COOH) is 1litre while the molar concentration is 0.5M

Molarity or Molar concentration is calculated using the formula:

M= n/V

Where; M= Molarity (M) = 0.5M

n= number of moles (mol)

V= Volume (V) = 1L

Hence, number of moles (n) = M × V

n = 0.5 × 1

n = 0.5 moles.

To calculate the mass in grams of CH3COOH, we say;

Number of moles (n) × molar mass (MM)

Since atomic mass for (C= 12, H= 1 and O=16)

Molar mass of CH3COOH:

= 12 + 1(3) + 12 + 16 + 16 + 1

Molar mass of CH3COOH = 60g/mol

Mass (in grams) of CH3COOH = 0.5 moles × 60g/mol

Mass = 30grams.

Therefore, 30grams of CH3COOH compound are required to make 1 liter of a 0.5 M solution.

6 0
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