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Marianna [84]
3 years ago
13

3 intersecting lines are shown. A horizontal line contains points R, A, T, S. Another line intersects at point A and also contai

ns D, A, C. Line A B extends away from the center of the other intersecting lines.
Analyze the diagram to answer the questions.

Another way to name AngleSAC would be Angle.



A point on ray AS is .



Line segment A R and Line segment A B create Angle.
Mathematics
1 answer:
svlad2 [7]3 years ago
4 0

Answer:

C or A I think it's correct

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Find the slope of the line passing through the points (-7, 8) and (5.-7).
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Answer:

slope is 15/-12

Step-by-step explanation:

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Find the value of x. 50 points
notka56 [123]
The answer is 138
Because the angle is 180 and what I did was 2 x 21 = 42 and I did 180-42 equals to 138
7 0
1 year ago
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ABCD is a quadrilateral such that the measures of three of its interior angles are given as B=122 degrees, C= 75 degrees, D= 51
posledela

Answer:

angle A is 112 degree.

Step-by-step explanation:

quadilateral have 4 angles .

sum of the interior angles of a quadilateral is 360 degree

Here,

angle A = be x

angle B = 122

angle C = 75

angle D = 51

Now,

angle A + angle B + angle C + angle D =360 degree

x + 122 + 75 + 51 = 360

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x = 360 - 248

x = 112

4 0
3 years ago
A drawing of a tree and a wall are in the image below.
mina [271]

Answer:

<em>Choice B. 16 feet.</em>

<em>The height of the tree is 16 ft</em>

Step-by-step explanation:

<u>Similar Triangles</u>

Similar triangles have their corresponding side lengths proportional by a fixed scale factor.

We are given the drawings of a tree and a wall and it's assumed both triangles are similar. We need to find the scale factor and find the height of the tree.

Comparing the corresponding distances from the viewer to the base of the tree and the base of the wall, we can calculate the scale factor as 24/6=4.

Applying the same factor to the height of the model, we get the height of the tree is 4*4 = 16 ft.

Choice B. 16 feet

The height of the tree is 16 ft

6 0
3 years ago
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Answer:

\boxed{\text{18 blocks}}

Step-by-step explanation:

Distance travelled on graph = AB + BC + CD + DA  

AB = CD  = (3 +2) = 5

BC = AD = 2 –(-2) = 4

Distance on graph = 2 × 5 + 2 × 4 = 10 + 8 = 18 spaces = 18 blocks

Bridgette jogs \boxed{\textbf{18 blocks}}each day.

8 0
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