For there to be 1 car, we consider two possible outcomes:
The first door opened has a car or the second door opened has a car.
P(1 car) = 2/6 x 4/5 + 4/6 x 2/5
P(1 car) = 8/15
For there to be no car in either door
P(no car) = 4/6 x 3/5
P(no car) = 2/5
Probability of at least one car is the sum of the probability of one car and probability of two cars:
P(2 cars) = 2/6 x 1/5
= 1/15
P(1 car) + P(2 cars) = 8/15 + 1/15
= 3/5

The answer is (3) -5 and 5.
Answer:
$4.50
Step-by-step explanation:
Please give brainliest!!
Answer:
The answer is 28 in
Step-by-step explanation:
I divided 392/14=28
hopefully it helps.
please mark brainliest.
Answer:
the awnser is either a or c
Step-by-step explanation:
i hope my awnser helps