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BartSMP [9]
3 years ago
10

What are all of the possible classifications for a 3 × 3 system? Check all of the boxes that apply.

Mathematics
2 answers:
Degger [83]3 years ago
7 0
Consistent and Dependent 
Consistent and Independent 
Inconsistent and Independent 
Alex_Xolod [135]3 years ago
6 0
I believe the answer would be inconsistent and dependent, and also inconsistent and independent. System of equations with three variables are either independent, dependent or inconsistent , each case can be established algebraically and represented graphically.
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I need help with #17
Orlov [11]
The van's consumption is 200/10  = 20 miles per gallon

so for 480 miles we need  480 / 20  = 24 gallons
3 0
3 years ago
Can someone please help with this or explain how to do it. I'm not very sure where to begin ToT
larisa86 [58]

Answer:

d. 12x^23y^40z^9 + 10x^78z^5 = 2x^23z^5(6y^40z^4 + 5x^55)

Step-by-step explanation:

First, we find the greatest common factor of 12x^23y^40z^9 and 10x^78z^5.

We work on the numbers, then on x, then on y, then on z.

We start with the GCF of 12 and 10.

10 = 2 * 5

12 = 2 * 3 * 3

The only factor 10 and 12 have in common is 2, so the GCF of 12 and 10 is 2.

Now we work on x. We have x^23 and x^78.

x^23 has 23 factors of x.

x^78 has 78 factors of x.

Since x^23 and x^78 have both at least 23 factors of x, x^23 is the GCF of x.

Now we work on y.

There is y^40 in one term, but there is no y in the other term. There is no GCF for the y.

Now we work on z. The first term has z^9. the second term has z^5. They both have at least 5 factors of z, so the GCF of z is z^5.

Now we put all the parts of the GCF together, and the GCF of the two terms is

2x^23z^5

We use option d. to factor.

12x^23y^40z^9 + 10x^78z^5 = 2x^23z^5(___a____ + ____b___)

We already have the GCF outside the parentheses. Now we need to figure out what goes inside the parentheses.

The terms that go in positions a and b are the terms that when multiplied by the GCF give you the original expression.

We now work on position a.

What do you multiply by 2x^23z^5 to get 12x^23y^40z^9?

Answer: 6y^40z^4

Now we have

12x^23y^40z^9 + 10x^78z^5 = 2x^23z^5(6y^40z^4 + ____b___)

Now we do the same for position b.

What do you multiply by 2x^23z^5 to get 10x^78z^5?

Answer: 5x^55

Now we have

12x^23y^40z^9 + 10x^78z^5 = 2x^23z^5(6y^40z^4 + 5x^55)

Answer: d. 12x^23y^40z^9 + 10x^78z^5 = 2x^23z^5(6y^40z^4 + 5x^55)

5 0
2 years ago
A rectangular parking lot has a length 20 H more
leva [86]

Let the width = X

The length would be X + 20

Area = Length x width:

2400 = x * (x+20)

Simplify:

2400 = x^2 + 20x

Subtract 2400 from both sides:

x^2 + 20x - 2400 = 0

Factor:

(x-40) (x+60) = 0

Solve for both x's:

x = 40 and x = -60

The dimensions of a parking lot have to be positive values so you would use x = 40.

The width = x = 40

The length = x +20 = 40+20 = 60

The dimension of the parking lot is 40H x 60H

4 0
3 years ago
Mark, Anthony, and Derek, are going on a road trip and will take turns driving the car. They need to decide who will drive first
finlep [7]

Answer: Option D

Step-by-step explanation:

I got it right on Edmentum/Plato

8 0
3 years ago
Olivia chose 10/21 . How did she get that answer?
Katyanochek1 [597]
Cuz she divided 23 and 8 and got 21 then she added 3+3= 6 + 4= 10
5 0
2 years ago
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