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tatyana61 [14]
3 years ago
10

A rectangular parking lot has a length 20 H more

Mathematics
1 answer:
leva [86]3 years ago
4 0

Let the width = X

The length would be X + 20

Area = Length x width:

2400 = x * (x+20)

Simplify:

2400 = x^2 + 20x

Subtract 2400 from both sides:

x^2 + 20x - 2400 = 0

Factor:

(x-40) (x+60) = 0

Solve for both x's:

x = 40 and x = -60

The dimensions of a parking lot have to be positive values so you would use x = 40.

The width = x = 40

The length = x +20 = 40+20 = 60

The dimension of the parking lot is 40H x 60H

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Answer:

The answer to your question is a = 40, b = 5/8

Step-by-step explanation:

Data

  ab = 25

  log₄a - log₄b = 3

Process

1.- Use the law log of a quotient

               log₄ a/b = 3

2.- Convert the log to an exponent

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                   a/b = 64      Equation l

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3.- Solve equation l for a

                  a = 64b

4.- Substitute in equation ll

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-Simplify

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-Solve for b

                         b² = 25/64

                         b = 5/8

5.- Substitute the value of b to find a

                     a = 64(5/8)

-Simplification

                     a = 40                        

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