I will do 9 only. You can do 11.
Question 9
sin(60) = x/8
sin(60)(8) = x
4•sqrt{3} = x
x^2 + y^2 = 8^2
(4•sqrt{3})^2 + y^2 = 64
16(3) + y^2 = 64
48 + y^2 = 64
y^2 = 64 - 48
y^2 = 16
sqrt{y^2} = sqrt{16}
y = 4
Do 11 the same way.
0 and 2 is the most logical answer
Answer:
c. ax+b=ax+b
Step-by-step explanation:
To know what equation has infinite solutions, you first try to simplify the equations:
a.
In this case you have that a must be different of b, but there is no restriction to the value of c, then c can be equal to a or b.
b.
Here you obtain that b = c. But the statement of the question says that a, b and c are three different numbers.
c.
In this case you have that whichever values of a, b and are available solutions of the equation. Furthermore, when you obtain 0=0, there are infinite solutions to the equation.
Then, the answer is:
c. ax+b=ax+b
2 consecutive even integers....x and x + 2
(x + 2) + 2x = 62
3x + 2 = 62
3x = 62 - 2
3x = 60
x = 60/3
x = 20
x + 2 = 20 + 2 = 22
ur 2 numbers are 20 and 22
9514 1404 393
Answer:
B reflected over y, translated up
Step-by-step explanation:
The left-right reversal means there was a reflection over a vertical line. The only one among the offered choices is the y-axis.
If the lines are reflected over the y-axis, the points on the y-axis don't move. The intercepts would still be 2 and 5 after the reflection.
However, the y-intercepts have moved up 3 units to 5 and 8.
Lines g and h were reflected over the y-axis and translated up 3 units.
