When simplified, 9x-(x+4) is what

Find the area of a regular octagon with side lengths of 17.2 m and an apothem length of 20.8 m.

jek_recluse [69]

Answer:

Pentagon a = 4.9 in. s = 7.1 in. /l ;/ >cvr'-. ~ j-?.1· '19~~. 5) Octagon a = 20.8 m s= 17.2m. ,4 ~;.>a-rt. ::: i, 17. z • t~f "g. ~ :::::, l'/?1 ,0 nt z, ... What is the length of the apothem to the nearest whole number

Step-by-step explanation:

Pentagon a = 4.9 in. s = 7.1 in. /l ;/ >cvr'-. ~ j-?.1· '19~~. 5) Octagon a = 20.8 m s= 17.2m. ,4 ~;.>a-rt. ::: i, 17. z • t~f "g. ~ :::::, l'/?1 ,0 nt z, ... What is the length of the apothem to the nearest whole number

5 0

3 years ago

Please help me answer thanks.

Dmitry_Shevchenko [17]

Answer:

see explanation

Step-by-step explanation:

Given that M is directly proportional to r³ then the equation relating them is

M = kr³ ← k is the constant of proportion

To find k use the condition when r = 4, M = 160, thus

160 = k × 4³ = 64k ( divide both sides by 64 )

2.5 = k

M = 2.5r³ ← equation of variation

(a)

When r = 2, then

M = 2.5 × 2³ = 2.5 × 8 = 20

(b)

When M = 540, then

540 = 2.5r³ ( divide both sides by 2.5 )_

216 = r³ ( take the cube root of both sides )

r = $\sqrt[3]{216}$ = 6

5 0

3 years ago

Gregory brought 11 pumpkins to school for pumpkin-carving contest. Each pumpkin

Zigmanuir [339]

Answer:

Step-by-step explanation:

I need help too

5 0

3 years ago

The water diet requires you to drink two cups of water every half hour from the time you get up until you go to bed, but otherwi

Elan Coil [88]

Answer:

$7-3.182 \frac{13.638}{\sqrt{4}}= -14.698$

$7+3.182 \frac{13.638}{\sqrt{4}}= 28.698$

Step-by-step explanation:

For this case we have the following info given:

Weight before diet 180 125 240 150

Weight after diet 170 130 215 152

We define the random variable $D = before-after$ and we can calculate the inidividual values:

D: 10, -5, 25, -2

And we can calculate the mean with this formula:

$\bar X= \frac{\sum_{i=1}^n X_i}{n}$

And the deviation with:

$s= \sqrt{\frac{\sum_{i=1}^n (X_i- \bar X)^2}{n-1}}$

And after replace we got:

$\bar D= 7, s_d = 13.638$

And the confidence interval for this case would be given by:

$\bar D \pm t_{\alpha/2} \frac{s_d}{\sqrt{n}}$

The degrees of freedom are given by:

$df = n-1= 4-1=3$

For the 95% of confidence the value for the significance is $\alpha=0.05$ and the critical value would be $t_{\alpha/2}= 3.182$ . And replacing we got:

$7-3.182 \frac{13.638}{\sqrt{4}}= -14.698$

$7+3.182 \frac{13.638}{\sqrt{4}}= 28.698$

6 0

3 years ago

How to do slope intercept form again?!

earnstyle [38]

I don't know what is the correct answer

3 0

3 years ago