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Svetllana [295]
3 years ago
5

16. A truck traveling 45 miles per hour and a train traveling 60 miles per hour cover the same distance. The truck travels 2 hou

rs longer than the train. How many hours does each travel?
What equation would represent the total distance traveled by both the train and the truck? [Hint: Remember the distance traveled formula d = rt.]

A. 105x + 90
B. 105x
C. 45x + 90
D. 60x
Mathematics
1 answer:
Snowcat [4.5K]3 years ago
7 0

Answer:

A.

Step-by-step explanation:

d = rt

If t is the time taken by the train, then the truck takes t+2 hours.

For the truck:

d = 45(t + 2)

For the train:

d =  60t

Total distance travelled by both:

= 2d

= 60t + 45(t + 2)

= 60t + 45t + 90

= 105t + 90      where t is the time taken by the train.

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1/5

1/10 / 1/2= 2/10
Then simplify it by 2, it becomes D.1/5
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4 0
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A circular flower bed is 19 m in diameter and has a circular sidewalk around it that is 4 m wide. Find the area of the sidewalk
yaroslaw [1]

Answer:

289 m²

Step-by-step explanation:

First find the area of the flower bed

A=πr²= (3.14)(9.5)² = 283.385

Then get the area of everything including the sidewalk

A=πr²= (3.14)(13.5)² = 572.265

Then subtract and you'll get the area of just the sidewalk

572.265 - 283.385 = 288.88m²

4 0
3 years ago
Read 2 more answers
May 06,
Andre45 [30]

Answer:

343 cubic inches

Step-by-step explanation:

7 times 7 times 7 is 343

3 0
2 years ago
Researchers at the National Cancer Institute released the results of a study that investigated the effect of weed-killing herbic
jolli1 [7]

Answer:

The 95% confidence interval for the difference in the proportion of cancer diagnoses between the two groups is (0.3834, 0.5166).

Step-by-step explanation:

Before building the confidence interval, we need to understand the central limit theorem and subtraction between normal variables.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean \mu = p and standard deviation s = \sqrt{\frac{p(1-p)}{n}}

Subtraction between normal variables:

When two normal variables are subtracted, the mean is the difference of the means, while the standard deviation is the square root of the sum of the variances.

The randomly sampled 400 dogs from homes where an herbicide was used on a regular basis, diagnosing lymphoma in 230 of them.

This means that:

p_h = \frac{230}{400} = 0.575, s_h = \sqrt{\frac{0.575*0.425}{400}} = 0.0247

Of 200 dogs randomly sampled from homes where no herbicides were used, only 25 were found to have lymphoma.

This means that:

p_n = \frac{25}{200} = 0.125, s_n = \sqrt{\frac{0.125*0.875}{200}} = 0.0234

Distribution of the difference:

p = p_h - p_n = 0.575 - 0.125 = 0.45

s = \sqrt{s_h^2+s_n^2} = \sqrt{0.0247^2 + 0.0234^2} = 0.034

Confidence interval:

The confidence interval is:

p \pm zs

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

The lower bound is 0.45 - 1.96(0.034) = 0.3834

The upper bound is 0.45 + 1.96(0.034) = 0.5166

The 95% confidence interval for the difference in the proportion of cancer diagnoses between the two groups is (0.3834, 0.5166).

3 0
3 years ago
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