∆ ABC is isosceles with AB= AC= 7.5cm and BC= 0 cm .the height AD from A to BC, is 6cm . find the area of ∆ ABC what will be the
1 answer:
I have attached an image of the triangle.
BC = 9 cm
Answer:
CE = 7.2 cm
Step-by-step explanation:
In the attached triangle, we see that;
AB = AC = 7.5cm
BC = 9 cm
AD = 6cm
BC = 9cm
Formula for area of triangle is given as;
A = ½bh
Where b is base and h is height.
For the ∆ ABC with BC as base,
Area = ½ × 9 × 6 = 27 m²
Similarly, For ∆ ABC with AB as base,
Area = ½ × 7.5 × CE
Now, area from earlier is 27 cm²
Thus;
½ × 7.5 × CE = 27
Multiply both sides by 2 to get;
7.5CE = 54
CE = 54/7.5
CE = 7.2 cm
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Answer: Surface area is equal to 200
Volume is equal to 333.33
Step-by-step explanation:
First, let's do surface area.
The surface area of a pyramid is equal to 1/2(perimeter of base)(lateral height) + area of the base
The perimeter of the base is 10(4) = 40; as the base is a square with a side length of 10.
The lateral height is given as 5 cm.
The area of the base is 10(10) = 100.
We can plug those numbers into the equation to get 1/2(40)(5) + 100, which comes out to be 200.
Now for volume.
The volume of a pyramid is equal to 1/3(area of the base)(height).
We already have the area of the base, which is 100.
The height is given as 10 cm.
Plugging those numbers into the equation, we get 1/3(100)(10), which is 1000/3 or about 333.33.
Hope this helps!