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AysviL [449]
3 years ago
5

A student draws a geometric shape where all of the sides are different lengths. which of the following geometric shapes could th

e student have drawn?
a. rhombus

b. trapezoid

c. isosceles triangle

d. equilateral triangle
Mathematics
2 answers:
Ipatiy [6.2K]3 years ago
6 0
A. This is not the answer because all four sides of a rhombus are the same length. We can rule out choice A

B. This is the answer because we can eliminate choice C and D. A trapezoid could have all four sides that are different in length as long as its not isosceles. 

C. An isosceles triangle has two sides that are the same length so we can rule this out

D. All three sides of any equilateral triangle are the same length, so we can rule this out.

-------------------------------------

So once again, the answer is choice B
Kay [80]3 years ago
5 0
A student draws a geometric shape where all of the sides are different lengths. which of the following geometric shapes could the student have drawn?

a. rhombus
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In a paragraph, explain what the domain and range is for the function f(x) = x2 + 4x - 21.
Nana76 [90]

Domain: Anything at all. All numbers and sub-divisions of a number line. - ∞ < x < ∞

The range is much harder. You could complete the square to get the range, which I will do after we get the answer. The simplest way to get the smallest part of the range is to graph the quadratic. The lowest point is at (-2, -25) so the range is

Range: -25 ≤ y < ∞

Completing the square.

y = x^2 + 4x - 21

y = (x^2 + 4x) - 21

y = (x^2 + 4x + (4/2)^2 ) - 21 - (4/2)^2

y = (x^2 + 4x + 4) - 21 - 4

y = (x + 2)^2 - 25

The minimum point is (- 2,-25) just as the graph predicted.


7 0
3 years ago
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lisabon 2012 [21]

Answer:

nose mate

Step-by-step explanation:

8 0
3 years ago
the perimeter of a pentagon (a five-sided polygon) is 50 in. the five sides are represented by consecutive integers. Find the le
posledela

Answer:

  8, 9, 10, 11, 12

Step-by-step explanation:

Consecutive integer problems are often easier to work if you consider average values. Here, the middle of the 5 consecutive integers is their average, which is 50/5 = 10.

This tells you the integer side lengths are 8, 9, <em>10</em>, 11, 12.

7 0
3 years ago
CAN SOMEONE PLEASE CHECK OVER THIS ??
uysha [10]
Honestly I think you are correct, not trying to take your point. :)
4 0
4 years ago
Read 2 more answers
Triangle A B C is shown. Angle A C B is a right angle. An altitude is drawn from point C to a point on side A B to form a right
mars1129 [50]

Answer:

BC=15\ units

Step-by-step explanation:

see the attached figure to better understand the problem

In the right triangle ABC

Applying the Pythagorean Theorem

AB^2=AC^2+BC^2

substitute the given values

17^2=8^2+BC^2

solve for BC

BC^2=17^2-8^2

BC^2=225

BC=15\ units

5 0
3 years ago
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