The probability of that occurring is 0%. There are 6 sides in a typical dice, which means the probability of rolling a 2 is 1/6th. (1/6)^1000 will give you the probability of rolling a 2 exactly 1000 times. (1/6)^1000 equates to 0%.
Answer:
C. 4 times x squared plus 6 times x minus 3 minus 12 over the quantity 2 times x plus 1
Step-by-step explanation:
f(x) = 8x^3 + 16x^2 − 15
g(x) = 2x + 1.
f(x) / g(x) = (8x^3 + 16x^2 − 15) / (2x + 1)
Using long division
Answer:
μy = $6.56 ; σy = 2.77
Step-by-step explanation:
Given the data :
Mean μx= $8.56
Standard Deviation σx ≈ 2.77
Profit, Y on pizza with current promo :
Price off on pizza = $2
Y = x - 2
μx = E(x) = $8.56
μy = μ(x - 2)
μy = μx - $2
μy = $8.56 - $2
μy = $6.56
For the standard deviation of y
σx ≈ 2.77
σy = σ(x - 2)
σy = σx - 2
Constants are treated as 0 for standard deviation
σy = 2.77
Solve for R by simplifying both sides of the equation, the isolating the variable.
R^2h=-r^2+v
Hello from MrBillDoesMath!
Answer:
8(v+3) ( -1/2 (sqrt(14) - 4 v) (4 v + sqrt(14)) )
Discussion:
Given
64v^3 + 192v^2 - 56 v - 168
Factor 64v^2 from the first two terms. Factor 56 from the last two terms:
64v^2(v+3) - 56(v + 3) => factor (v+3) from both terms
(v+3) (64v^2 - 56) => factor 8 from both terms in the right ()
8(v+3)(8v^2-7) => factor 8y^2-7
8(v+3) ( -1/2 (sqrt(14) - 4 v) (4 v + sqrt(14)) )
Thank you,
MrB
