Answer: No solution for V. No solution.
Step-by-step explanation:
-v+5+6v=1+5v+3
Combine like terms together by adding all of the v's together, and number together.
5v+5=4+5v
5v-5v+5=4
0+5=4
5=4
Since this is a false statement, then no solution for V
Answer:
4x + 9. Given f(x) = 2x + 3 and g(x) = –x2 + 5, find (g o g)(x). (g o g)(x) = g(g(x)) ... Given f (x) = sqrt(x) and g(x) = x – 2, find the domains of ( f o g)(x) and (g o f )(x). Since f (x) involves a square root, the inputs have to be non-negative. ... Given h(x) = (x + 1)2 + 2(x + 1) – 3, determine two functions f (x) and g(x
Step-by-step explanation:
Answer:
1/sqrt10
Step-by-step explanation:
1) Find out cosA using formula (cosA)^2+(sinA)^2=1
The module of cosA= sqrt (1- (-3/5)^2)= sqrt 16/25=4/5
So cosA=-4/5 or cosA=4/5.
Due to the condition 270degrees< A<360 degrees, 0<cosA<1 that's why cosA=4/5.
2) Find sinA/2 using a formula cosA= 1-2sinA/2*sinA/2 where cosA=4/5.
(sinA/2)^2= 0.1
sinA= sqrt 0.1= 1/ sqrt10 or sinA= - sqrt 0.1= -1/sqrt10
But 270°< A< 360°, then 270/2°<A/2<360/2°
135°<A/2<180°, so sinA/2 must be positive and the only correct answer is
sin A/2= 1/sqrt10
11*57+X(1+2+3+.....+56)
=11*57+X(1+56)*56/2
=627+1596X
=19779
X=(19779-627)/1596=12
Your answer is C
Hey, using y2-y1/x2-x1 you know that slope has to be -1/4
