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Troyanec [42]
3 years ago
6

-v+5+6v=1+5v+3 solve for v

Mathematics
1 answer:
earnstyle [38]3 years ago
3 0

Answer: No solution for V.  No solution.

Step-by-step explanation:

-v+5+6v=1+5v+3

Combine like terms together by adding all of the v's together, and number together.

5v+5=4+5v

5v-5v+5=4

0+5=4

5=4

Since this is a false statement, then no solution for V

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A cone has a volume of 5 cubic inches. What is the volume of a cylinder that the cone fits exactly inside of?
Naya [18.7K]
<span>Volume of Cone: 1/3 Bh where B is the area of the base 1/3 Bh = 5 Bh = 15 B = 15/h The cylinder has the same base area as the cone. Volume of Cylinder: V = B*h B = V/h and B = 15/h The height of the cone and the cylinder are the same. V/h = 15/h Volume of Cylinder = 15.</span>
4 0
3 years ago
Helppppppppppp. Pleaseeeeeeeeeeeeeeeeeeeeeeeeeeee
olga55 [171]

Answer:

7

Step-by-step explanation:

form a proportion

12/2=42/x

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6 0
3 years ago
Read 2 more answers
Simplify (9x^3-4x+10)+(x^3+10x-9)
Alex

Simplify

9x^3 - 4x + 10 + x^3 + 10x - 9

Collect like terms

(9x^3 + x^3) + (-4x + 10x) + (10 - 9)

Simplify

<u>10x^2 + 6x + 1</u>

6 0
3 years ago
A TV station claims that 38% of the 6:00 - 7:00 pm viewing audience watches its evening news program. A consumer group believes
Elena L [17]

Answer:

z=\frac{0.340 -0.38}{\sqrt{\frac{0.38(1-0.38)}{830}}}=-2.374  

p_v =P(Z  

So the p value obtained was a very low value and using the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of people that regularly watch the TV station’s news program is significantly less than 0.38 .  

Step-by-step explanation:

1) Data given and notation

n=830 represent the random sample taken

X=282 represent the people that regularly watch the TV station’s news program

\hat p=\frac{282}{830}=0.340 estimated proportion of people that regularly watch the TV station’s news program

p_o=0.38 is the value that we want to test

\alpha=0.05 represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the proportion is less than 0.38:  

Null hypothesis:p\geq 0.38  

Alternative hypothesis:p < 0.38  

When we conduct a proportion test we need to use the z statisitc, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.340 -0.38}{\sqrt{\frac{0.38(1-0.38)}{830}}}=-2.374  

4) Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.05. The next step would be calculate the p value for this test.  

Since is a left tailed test the p value would be:  

p_v =P(Z  

So the p value obtained was a very low value and using the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of people that regularly watch the TV station’s news program is significantly less than 0.38 .  

3 0
3 years ago
I have 2 questions.
frosja888 [35]
I dont know the first answer but the 2nd is dad
6 0
3 years ago
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