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Aleks04 [339]
3 years ago
6

Find the domain of the function (f/g)(x) where f(x)=√x+1, g(x)=√x-9

Mathematics
1 answer:
nadya68 [22]3 years ago
4 0

Answer:

4x + 9. Given f(x) = 2x + 3 and g(x) = –x2 + 5, find (g o g)(x). (g o g)(x) = g(g(x)) ... Given f (x) = sqrt(x) and g(x) = x – 2, find the domains of ( f o g)(x) and (g o f )(x). Since f (x) involves a square root, the inputs have to be non-negative. ... Given h(x) = (x + 1)2 + 2(x + 1) – 3, determine two functions f (x) and g(x

Step-by-step explanation:

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Which function is represented in this graph?
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Answer:

y = tan (1/2 x - π/2) ⇒ the answer is (b)

Step-by-step explanation:

* Lets talk about the tangent function

- The tangent has a period of π, with each period separated by

 a vertical asymptote. The concept of "amplitude" doesn't

  really exist because -∞ < y < ∞

- You can transform the graph for tangent

∵ y = A tan B(x + C) + D

* Where:

# A, changes amplitude. (A always = 1)

# B determines the period.

# C determines how the graph is shifted from left to right.

  (horizontally)

# D determines how the graph is shifted up or down.(vertically)

∵ The basic function is y = tanФ has an amplitude of 1.

   It has a period of π. It has no phase or vertical shifts,

   because it is centered on the origin.

* Look to the problem

- From the graph:

- The period is 2π

∵ Period = π/B

∴ 2π = π/B ⇒ ÷ π

∴ 2 = 1/B

∴ B = 1/2

- the starting point of the function is at π instead of zero

∴ It moves π units to the right

∴ C = -π

∴ y = tan 1/2(x - π)

∴ y = tan (1/2 x - π/2)

* The function is ⇒ y = tan (1/2 x - π/2)

* The blue represents y = tanx

  The red represents y = tan (1/2 x - π/2)

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