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Aleks04 [339]
4 years ago
6

Find the domain of the function (f/g)(x) where f(x)=√x+1, g(x)=√x-9

Mathematics
1 answer:
nadya68 [22]4 years ago
4 0

Answer:

4x + 9. Given f(x) = 2x + 3 and g(x) = –x2 + 5, find (g o g)(x). (g o g)(x) = g(g(x)) ... Given f (x) = sqrt(x) and g(x) = x – 2, find the domains of ( f o g)(x) and (g o f )(x). Since f (x) involves a square root, the inputs have to be non-negative. ... Given h(x) = (x + 1)2 + 2(x + 1) – 3, determine two functions f (x) and g(x

Step-by-step explanation:

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ra1l [238]
To get the *percent increase* from week 1 to week 2, we calculate the change in distance from week 1 to week 2 (13.5 - 12.5 = 1 mile) over the week 1 distance (12.5 miles). Doing that, we find that Matthew increased his distance by

1/12.5 = 0.08, or 8%

We’re given that he’ll increase his distance by the same percentage from week 2 to 3, so to find his week 3 distance, we can find 8% of the week 2 distance and add that on. 8% of 13.5 miles is 0.08 x 13.5 = 1.08 miles, so by week 3, he’ll be running 13.5 + 1.08 = 14.58 miles.
4 0
3 years ago
What is bigger 1/3 or 3/5
raketka [301]

Method\ 1:

\dfrac{1}{3}=\dfrac{1\cdot5}{3\cdot5}=\dfrac{5}{15}\\\\\dfrac{3}{5}=\dfrac{3\cdot3}{5\cdot3}=\dfrac{9}{15}\\\\\dfrac{3}{15} < \dfrac{9}{15}\ therefore\ \dfrac{3}{5}\ is\ bigger


Method\ 2:

\dfrac{1}{3} < \dfrac{1}{2}=\dfrac{1.5}{3}\\\\\dfrac{3}{5} > \dfrac{1}{2}=\dfrac{2.5}{5}\\\\therefore\ \dfrac{3}{5}\ is\ bigger

6 0
3 years ago
X/2.1 = -1.8<br><br> Show your work and check it (write it out plz)
Lerok [7]
X = -1.8 * 2.1
x = 3.78

don't know how i can write it longer
7 0
3 years ago
This stuff confuses me
Slav-nsk [51]
It's slope would be undefined.
6 0
3 years ago
Read 2 more answers
Write the number eleven and six hundred fifty-one thousandths in standard form.
sweet-ann [11.9K]
The standard form of thr number is 11.651
5 0
4 years ago
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