Answer:
Step-by-step explanation:
step 1
Find the slope of the given line
we have
isolate the variable y
The slope of the given line is
step 2
Find the equation of the line that goes through the point (1,5) and is parallel to the given line
Remember that
If two lines are parallel then their slopes are equal
therefore
we have
substitute in the equation of a line in slope intercept form
solve for b
substitute
Yes it does my dear child
A 2/5 or 2:3
b 25% or 1/4
im 90% sure this is correct
Any line can be expresses as:
y=mx+b where m=slope=(y2-y1)/(x2-x1) and b=y-intercept (value of y when x=0)
First find the slope:
m=(2-0)/(8-0)=2/8=1/4 so we have thus far:
y=0.25x+b, we solve for b using any point on the line, (8,2)
2=0.25(8)+b
2=2+b
0=b
So the line is:
y=.25x which they might also express as y=x/4
The answer is E. (1/4)x
We break down the area into two triangles - since we're given all their side lengths, we use Heron's formula: ![[area]=\sqrt{s(s-a)(s-b)(s-c)},](https://tex.z-dn.net/?f=%5Barea%5D%3D%5Csqrt%7Bs%28s-a%29%28s-b%29%28s-c%29%7D%2C)
where 
![[ABD]=\sqrt{(265)(115)(85)(65)}\approx 12975.92](https://tex.z-dn.net/?f=%5BABD%5D%3D%5Csqrt%7B%28265%29%28115%29%2885%29%2865%29%7D%5Capprox%2012975.92)
![[CBD]=\sqrt{(225)(125)(75)(25)}\approx 7261.84](https://tex.z-dn.net/?f=%5BCBD%5D%3D%5Csqrt%7B%28225%29%28125%29%2875%29%2825%29%7D%5Capprox%207261.84)
![[ABCD]=[ABD]+[CBD]\approx\boxed{20238\,\text{m}^2}.](https://tex.z-dn.net/?f=%5BABCD%5D%3D%5BABD%5D%2B%5BCBD%5D%5Capprox%5Cboxed%7B20238%5C%2C%5Ctext%7Bm%7D%5E2%7D.)
