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kifflom [539]
3 years ago
7

-11+13r+6q-3r-3q+13 please help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics
1 answer:
Nadya [2.5K]3 years ago
7 0

Answer: <em>3q+10r+2</em>

Step-by-step explanation:

<em>You need to combine like terms/simplify</em>

<em>so lets combine:</em>

<em>6q and -3q</em>

<em>13r and -3r</em>

<em>-11 and 13</em>

<em>3q+10r+2</em>

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What is the quotient of 4 and 1/6 in the simplest form? 1/24
MakcuM [25]
SOLUTION:

Let's first establish the problem we will solve.

= 4 ÷ 1 / 6

Now we will turn this from division into multiplication by changing the division symbol ( ÷ ) into a multiplication symbol ( × ) and doing the reciprocal of the fraction after the symbol. Reciprocal basically means to make the numerator the denominator and make the denominator the numerator in the fraction.

= 4 × 6

Now we will simply write the product of the two numbers to achieve our final answer.

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Hope this helps! :)
Have a lovely day! <3
4 0
3 years ago
What would this be after you simplify?<br><br> x^0 y^5<br> -----------<br> y^5 z^-7
Kay [80]

Answer:

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3 0
3 years ago
Simplify this i need help
Temka [501]

Answer:

Step-by-step explanation:

√2x(7 + √2x)

7√2x + √2x ·√2x

7√2x + 2x

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6 0
3 years ago
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NNADVOKAT [17]
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4 0
3 years ago
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Find the distance between the points with the given coordinates (-4, 9) and (1, -3).
Dmitriy789 [7]

Answer: 13

Step-by-step explanation:

The formula for finding distance between two points is given by :

D = \sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}

x_{1} = -4

x_{2} = 1

y_{1} = 9

y_{2} = -3

Substituting the values into the formula , we have :

D = \sqrt{(1 -(-4))^{2} +(-3-9)^{2}}

D = \sqrt{(5)^{2}+(-12)^{2}}

D = \sqrt{25+144}

D = \sqrt{169}

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Therefore : the distance between the points is 13

7 0
3 years ago
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