The following that could be used to calculate the total volume of grains that can be stored in the silo is π(2 ft)²8 ft + 1/3π(2 ft)²(9.5 ft - 8ft)
To answer the question, we need to know what volume is.
<h3>What is volume?</h3>
This is the capacity of a material or container.
Since the silo is made of a cylindrical and a conical part, we need to find the volume of both parts.
<h3>Volume of cylindrical part.</h3>
So, the volume of the cylindrical part V = πr²h where
- r = radius of cylidrical part = 4 ft/2 = 2 ft and
- h = length of cylindrical part = 8 ft.
So, V = πr²h
V = π(2 ft)²8 ft
<h3>Volume of the conical part</h3>
The volume of the conical part is given by V' = 1/3πr²h where
- r = radius of cone = 2ft and
- h = height of cone.
Since the entire length of silo is 9.5 ft and length of cylindrical part is 8 ft, then the height of cone is h' = 9.5 ft - 8 ft
So, V' = 1/3πr²h'
V' = 1/3π(2 ft)²(9.5 ft - 8ft)
<h3>Total volume of grains in silo</h3>
The total volume of grains equals the total volume of the silo V" = V + V'
V" = π(2 ft)²8 ft + 1/3π(2 ft)²(9.5 ft - 8ft)
So, the following that could be used to calculate the total volume of grains that can be stored in the silo is π(2 ft)²8 ft + 1/3π(2 ft)²(9.5 ft - 8ft)
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