Answer:
Maximum error for viscosity is 17.14%
Step-by-step explanation:
We know that everything is changing with respect to the time, "r" is changing with respect to the time, and also "p" just "v" will not change with the time according to the information given, so we can find the implicit derivative with respect to the time, and since
The implicit derivative with respect to the time would be
If we multiply everything by dt we get
Remember that the error is given by 
therefore doing some algebra we get that
Since, r = 0.006 , dr = 0.00025 , p = 4*105 , dp = 2000 we get that
Which means that the maximum error for viscosity is 17.14%.
Answer:
5y^2 + 10y + 5x^2
Step-by-step explanation:
there's only two like terms that can be combined.
<h3>1.</h3>
The picture shows 5 groups of 3 bars. Each bar represents 1/10. We take the picture to mean that ...
... (15/10) / 5 = 3/10
In decimal:
... 1.5 / 5 = 0.3
<h3>2.</h3>
The picture shows 3 groups of 2 bars. Each bar represents 1/10. We take the picture to mean that ...
... (6/10) / 3 = 2/10
In decimal:
... 0.6 / 3 = 0.2
<h3>3.</h3>
The picture shows 4 groups, each consisting of 1 large square, 1 bar, and 4 small squares. We take the picture to mean that ...
... (4 + 4/10 + 16/100) / 4 = 1 + 1/10 + 4/100
In decimal:
... 4.56 / 4 = 1.14
Please note that 16/100 is equivalent to 1/10 + 6/100. In order to do the division, one of the 1/10 bars needed to be changed into 10 small squares, 10/100.
<h3>4.</h3>
The picture shows 3 groups, each consisting of 1 large square, 3 bars, and 2 small squares. We take the picture to mean that ...
... (3 + 9/10 +6/100) / 3 = 1 +3/10 + 2/100
In decimal:
... 3.96 / 3 = 1.32
To find range, you must find the largest number in your data, and subtract it by the smallest number in your data.
In this case...
the Largest (20) - smallest (0) = Range
