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The area of the circle A and B is 86.54 inches and 124.62 mm
According to the statement
we have given that the radius of the circle A and b and we have to find the area of the given circle.
So, we know that the
The area enclosed by a circle of radius r is πr².
So, For area of the circle
For condition A :
diameter = 10.5 inches
then radius = 5.25
Area = πr²
Area = 3.14*27.56
Area = 86.54 inches
Now, For condition B :
radius = 6.3 mm
Area = πr²
Area = 3.14*39.69
Area = 124.62mm
So, The area of the circle A and B is 86.54 inches and 124.62 mm
Learn more about area of the circle here
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2x^2-y
Plug in the values.
2(3)^2-(-2)
2(3)^2+2
Exponents first.
2*9+2
18+2
20
The answer is 20.
I hope this helps!
~kaikers
The solution(s) of a system of linear equations give points of intersection of specific lines or planes.
The solution(s) of a system of linear inequalities give areas of intersection wherein any specific pair of points or lines are solutions.
PROCESS-WISE there are little differences between solving systems. However, multiplication and division by negatives reverses the signs in inequalities.
<u> Answer I got for this was 16.
Subtract the 1/4 from the 3/4 and get 2/4, simplified: 1/2
You should have 1/2 h -9 = -1 by now,
Then add nine to the other side, getting 8.
You should have 1/2 h = 8.
Then divide 1/2 by 8.
8/1÷1/2 ---> 8/1 × 2/1 (you flip the fraction when you divide)
So your answer is 16!
Hopefully that helped!</u>
