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kozerog [31]
3 years ago
8

Which is a factor of each term of the polynomial? (72−12) CLEAR CHECK 7 2 7

Mathematics
1 answer:
Inessa [10]3 years ago
3 0

Answer:

12

Is the greatest factor

Step-by-step explanation:

All factors include

2,3,4,6,12

Thats it

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How can you solve the equation 4−x = 2x + 3 graphically?
pychu [463]

Answer:

x = 1/3

Step-by-step explanation:

Hello,

we can draw the two lines defined by

   y = 4 - x

   y = 2x + 3

And search for the intersection point as below

This is the point A (1/3, 11/3)

Do not hesitate if you have any question

Thanks

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3 years ago
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PLS HELP BRAINLIST and 100 POINTS
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Answer:

B, He is -40 due to it asking which number is his point. If he was positive 40 then he would be on an island or flying in the sky. Your answer is -40

3 0
2 years ago
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Cars arrive at the Wendy's drive-through at a rate of 1 car every 5 minutes between the hours of 11:00 PM and 1:00 AM. on Saturd
mestny [16]

Answer:

1) P(X = 8) = 0.1033

P(X = 9) = 0.0688

2) Expected number of 200 restaurants in which exactly 8 customers use the drive-through: 20.66

Expected number of 200 restaurants in which exactly 9 customers use the drive-through: 13.76

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given time interval.

Question 1. Use the Poisson distribution to calculate the probability that exactly 8 cars will use the drive-through between 12:00 midnight and 12:30 AM on a Saturday night at Wendy's. Do the same for exactly 9 cars.

Cars arrive at the Wendy's drive-through at a rate of 1 car every 5 minutes between the hours of 11:00 PM and 1:00 AM. on Saturday nights. This means that during 30 minutes, 6 cars expected to arrive. So \mu = 6.

P(X = 8)

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 8) = \frac{e^{-6}*(6)^{8}}{(8)!} = 0.1033

P(X = 9)

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 9) = \frac{e^{-6}*(6)^{9}}{(9)!} = 0.0688

Question 2. At how many of the 200 restaurants in the survey would you expect exactly 8 customers to use the drive-through? exactly 9 customers?

There is a 10.33 probability that 8 customers would use the drive through for each restaurant.

So of 200, the expected number is

E(X) = 200*0.1033 = 20.66

There is a 6.88 probability that 9 customers would use the drive through for each restaurant.

So of 200, the expected number is

E(X) = 200*0.0688 = 13.76

8 0
3 years ago
Can someone pls help me
ipn [44]
I think it 48 i’m not sure
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3 years ago
Explain part a and b
xxTIMURxx [149]
As i can see there is a table a bove so the x is the first number which going up the graph and the y is across the line
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