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3 years ago

PLEASE SOMEONE DO THIS QUESTION FOR ME ASAP!! GIVING BRAINLIEST

Mathematics

2 answers:

Nikolay [14]3 years ago

3 0

Answer:

5:15

Step-by-step explanation:

Ainat [17]3 years ago

3 0

My phone is cracked and i can’t see the question, sorry!

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Help please it would help my grade alot

Alexxandr [17]

Answer:

It cooled 58.4 degrees

Step-by-step explanation:

T(t) = 68 + 144e ^(-.052t)

We want to find the value when t= 10

T(10) = 68 + 144e ^(-.052*10)

= 68 +85.611

T(10) =153.611

We also need to know

T(0)= 68 + 144e ^(-.052*0)

=68+144

=212

We want to know how much it cools

That would be the temperature at time 0 minus the temperature at time 10

T(0) - T (10)

212-153.611

58.389

To the nearest tenth

58.4 degrees

3 0

3 years ago

Factor n(2n+3)+4(2n-3)

zavuch27 [327]

The answer would be 2n^2+3n+ 8n-1

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3 years ago

Jillian invested $2000 in an account with a 1.25% annual

Dennis_Churaev [7]

Answer:

the balance is 2075 dollars

Step-by-step explanation:

The answer is 2075 because 1.25% of 2000 is 25 and 25 multiplied by 3 is 75 and 75 plus 2000 is 2075.

P.S Can I have brainliest?

5 0

3 years ago

What is the slope of the line on the graph?<br> <br> Enter your answer in the box.

yulyashka [42]

The slope of this triangle is -2/1

6 0

3 years ago

Read 2 more answers

Solve step by step solution then only i can do it plxx

Anuta_ua [19.1K]

Answer:

<h3><u>Let's</u><u> </u><u>understand the concept</u><u>:</u><u>-</u></h3>

Here angle B is 90°

So $\triangle ABC$ and $\triangle ABD$ Are right angled triangle

So we use Pythagoras thereon for solution

<h3><u>Required Answer</u><u>:</u><u>-</u></h3>

First in triangle ABC

perpendicular=p=8cm

Hypontenuse =h =10cm

We need to find base=b

According to Pythagoras thereon

${\boxed{\sf b^2=h^2-p^2}}$

Substitutethe values

$\longrightarrow$ $\sf b^2=10^2-p^2$

$\longrightarrow$ $\sf b={\sqrt {10^2-8^2}}$

$\longrightarrow$ $\sf b={\sqrt{100-64}}$

$\longrightarrow$ $\bf b={\sqrt {36}}$

$\longrightarrow$ $\sf b=6$

$\therefore$ $\overline{BC}=6cm$

BD=BC+CD

$\longrightarrow$ $BD=9+6$

$\longrightarrow$ $BD=15cm$

Now in $\triangle ABD$

Perpendicular=p=8cm

Base =b=15cm

We need to find Hypontenuse =AD(x)

According to Pythagoras thereon

${\boxed {\sf h^2=p^2+b^2}}$

Substitute the values

$\longrightarrow$ $\sf h^2=8^2+15^2$

$\longrightarrow$ $\sf h={\sqrt {8^2+15^2}}$

$\longrightarrow$ $\sf h={\sqrt {64+225}}$

$\longrightarrow$ $\sf h={\sqrt {289}}$

$\longrightarrow$ $\sf h=17cm$

$\therefore$ ${\underline{\boxed{\bf x=17cm}}}$

3 0

3 years ago