Answer:
D. (4,3)
Step-by-step explanation:
I calculated it logically
The given above may be modeled by the arithmetic sequence with initial value (I) 2200 and common difference (d) of 70. The number of applicants every year can be written by the equation,
at = a1 + (n - 1) x d
From the given above, n is equal to 4. This corresponds to the term which is 3 years from now.
at = 2200 + (4 - 1) x 70 = 2410
Thus, the enrollment capacity would be 2410 students.
Answer:
if your going based off of the path that they are taking i say yes because the will meet at the end point or in this case the 1 yard line
Step-by-step explanation:
