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Ad libitum [116K]
2 years ago
14

Reporting Category: Geometry Standard: 10 G.3 Recognize and solve problems involving angles formed by transversals of coplanar l

ines. Identify and determine the measure of centrai and inscribed angles and their associated minor and major aros. Recognize and solve problems associated with radii, chords, and arcs within or on the same circle. Standard: Ccss Math. Content 8.G.A.s- use informaf arguments to establish facts about the angle sum and exterior angle of triangles, about the angles created when parallel lines are cut by a transversal, and the angle-angle criterion for similarity of triangles, For example, arrange three copies of the same triangle so that the sum of the three angles appears to farm a line, and give an argument in terms of transversals why this is so. Parallel lines q and m are cut by transversal lines jand k. The lines, and the measures of some of the angles created by the intersections of the lines, are shown in the diagram below. 110 1159 2 ON a. What is the measure, in degrees, of 21? Show or explain how you got your answer. b. What is the measure, in degrees, of L3? Show or explain how you got your answer. what is the measure, in degrees, of 25? Show or explain how you got your answer. d. What is the measure, in degrees, of 6? show or explain how you got your answer

Mathematics
1 answer:
Alexxx [7]2 years ago
4 0
The measure in degrees would be 15<span />
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The answer is 5.8 times a second

Step-by-step explanation:

Divide 1044 by 180 (The number of seconds in 3 minutes)

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Determine the singular points of the given differential equation. Classify each singular point as regular or irregular. (Enter y
ludmilkaskok [199]

Answer:

Step-by-step explanation:

Given that:

The differential equation; (x^2-4)^2y'' + (x + 2)y' + 7y = 0

The above equation can be better expressed as:

y'' + \dfrac{(x+2)}{(x^2-4)^2} \ y'+ \dfrac{7}{(x^2- 4)^2} \ y=0

The pattern of the normalized differential equation can be represented as:

y'' + p(x)y' + q(x) y = 0

This implies that:

p(x) = \dfrac{(x+2)}{(x^2-4)^2} \

p(x) = \dfrac{(x+2)}{(x+2)^2 (x-2)^2} \

p(x) = \dfrac{1}{(x+2)(x-2)^2}

Also;

q(x) = \dfrac{7}{(x^2-4)^2}

q(x) = \dfrac{7}{(x+2)^2(x-2)^2}

From p(x) and q(x); we will realize that the zeroes of (x+2)(x-2)² = ±2

When x = - 2

\lim \limits_{x \to-2} (x+ 2) p(x) =  \lim \limits_{x \to2} (x+ 2) \dfrac{1}{(x+2)(x-2)^2}

\implies  \lim \limits_{x \to2}  \dfrac{1}{(x-2)^2}

\implies \dfrac{1}{16}

\lim \limits_{x \to-2} (x+ 2)^2 q(x) =  \lim \limits_{x \to2} (x+ 2)^2 \dfrac{7}{(x+2)^2(x-2)^2}

\implies  \lim \limits_{x \to2}  \dfrac{7}{(x-2)^2}

\implies \dfrac{7}{16}

Hence, one (1) of them is non-analytical at x = 2.

Thus, x = 2 is an irregular singular point.

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3 years ago
The coordinates of the point that is a reflection of Y(-4, -2) across the x-axis are ( , ). The coordinates of the point that is
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Answer:

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Step-by-step explanation:

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It should be an L shape.

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