All categories

3 years ago

A-15=4a-3 if u dont want spam then dont answer

Mathematics

1 answer:

balu736 [363]3 years ago

7 0

Answer:

they deleted my answer :(

Step-by-step explanation:

You might be interested in

Jeff is baking a cake. The recipe says that he has to mix 32 grams of vanilla powder to the flour.

sergeinik [125]

If 1 cup of that particular vanilla powder has a mass of 128 grams, then $\dfrac{2}{3}$ of a cup of vanilla powder has a mass of

$\dfrac{2}{3} \cdot 128=\dfrac{256}{3}=85\dfrac{1}{3}$ grams.

Since

$85\dfrac{1}{3}-32=53\dfrac{1}{3}$ grams and $\dfrac{5}{12}$ of a cup of vanilla powder is

$\dfrac{5}{12}\cdot 128=\dfrac{5\cdot 128}{12}=\dfrac{5\cdot 32}{3}=\dfrac{160}{3}=53\dfrac{1}{3},$

then correct answer is that he went over by $\dfrac{5}{12}$ of a cup.

Answer: correct choice is B.

3 0

3 years ago

Read 2 more answers

A basketball hoop witha circumference of 56.52 inches i need to find the diameter

MA_775_DIABLO [31]

Answer:

Exactly, It would be this: 8.99543738355 . But rounded is 9 or 8.99

5 0

2 years ago

What is the equation in point slope form of the line that passes through the point (−1, −3) and has a slope of 4?

Firlakuza [10]

Answer:

(y-(-3))=4(x-(-1))

Step-by-step explanation:

formula for point slope form is:

y-y1=m(x-x1)

just plug in numbers from the point (-1, -3) for x1 and y1. The slope 4, would plug into m.

6 0

3 years ago

This week Jerome earned 252.50 in all. What was the dollar amount of the meals that Jerome served

Natasha2012 [34]

Answer:

Step-by-step explanation:

$ 449.75

6 0

3 years ago

A student is given that point P(a, b) lies on the terminal ray of angle Theta, which is between StartFraction 3 pi Over 2 EndFra

Harman [31]

Answer:

A.

The student made an error in step 3 because a is positive in Quadrant IV; therefore,

$cos\theta = \frac{a\sqrt{a^2 + b^2}}{a^2 + b^2}$

Step-by-step explanation:

Given

$P\ (a,b)$

$r = \± \sqrt{(a)^2 + (b)^2}$

$cos\theta = \frac{-a}{\sqrt{a^2 + b^2}} = -\frac{\sqrt{a^2 + b^2}}{a^2 + b^2}$

Required

Where and which error did the student make

Given that the angle is in the 4th quadrant;

The value of r is positive, a is positive but b is negative;

Hence;

$r = \sqrt{(a)^2 + (b)^2}$

Since a belongs to the x axis and b belongs to the y axis;

$cos\theta$ is calculated as thus

$cos\theta = \frac{a}{r}$

Substitute $r = \sqrt{(a)^2 + (b)^2}$

$cos\theta = \frac{a}{\sqrt{(a)^2 + (b)^2}}$

$cos\theta = \frac{a}{\sqrt{a^2 + b^2}}$

Rationalize the denominator

$cos\theta = \frac{a}{\sqrt{a^2 + b^2}} * \frac{\sqrt{a^2 + b^2}}{\sqrt{a^2 + b^2}}$

$cos\theta = \frac{a\sqrt{a^2 + b^2}}{a^2 + b^2}$

So, from the list of given options;

The student's mistake is that a is positive in quadrant iv and his error is in step 3

3 0

3 years ago