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slava [35]
3 years ago
15

A new shirt costs $14.99. If the shirt in sale for 1/5 off its price, about much would you save. SOLUTION PLS

Mathematics
2 answers:
amm18123 years ago
7 0
1/5 of 14.99=amount saved
1/5*14.99=$2.998 or $3
you would save 3 dollars
Tasya [4]3 years ago
5 0

Answer:

As per the given condition:

A new shirt costs $14.99.

If the shirt has a sale for \frac{1}{5} off its price.

Now, we find how much you save on this shirt:

First find the \frac{1}{5} of $14.99

i.e,  

\frac{1}{5} \times \$14.99 = \frac{\$14.99}{5} =\$ 2.998

⇒ you have the discounted value is $ 3 .

You pay for the shirt is: $14.99 -$ 2.998 = $11.992

Therefore, you would save $2.998 or $ 3 in buying your new shirt.


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ExtremeBDS [4]
The answer is B. x<7
3 0
3 years ago
Cushman Company had $838,000 in sales, sales discounts of $12,570, sales returns and allowances of $18,855, cost of goods sold o
Zepler [3.9K]

Answer:

Net income equals: $120,075.

Step-by-step explanation:

The net income is equal to:

+Sales

-Sales discounts

-Sales returns and allowances

-Cost of goods cold

-Operating expenses.

Computing all these values, we have:

Net income =Sales - (Sales discounts+Sales returns and allowances+Cost of goods cold+Operating expenses)

NI=838,000-(12,570+18,855+398,050+288,270)\\\\NI=838,000-717,925\\\\NI=120,075

The net income equals to $120,075.

4 0
3 years ago
Show that there do not exist scalar c1 c2 and c3 c1(-2,9,6)+c2(-3,2,1)+c3(1,7,5)= (0,5,4)​
fredd [130]

This is the same as showing the following system of equations doesn't have a solution:

\begin{cases}-2c_1-3c_2+c_3 = 0 \\ 9c_1 + 2c_2 + 7c_3 = 5 \\ 6c_1 + c_2 + 5c_3 = 4\end{cases}

or in matrix form,

\begin{bmatrix}-2&9&6\\-3&2&1\\1&7&5\end{bmatrix}\begin{bmatrix}c_1\\c_2\\c_3\end{bmatrix} = \begin{bmatrix}0\\5\\4\end{bmatrix}

The quickest way to check if there is a solution is to check whether the coefficient matrix is invertible. If its determinant is 0, then it is not invertible.

And the quickest way to show that the determinant is 0 is by observing that the third row is a linear combination of the first two rows:

(-2, 9, 6) - (-3, 2, 1) = (-2 + 3, 9 - 2, 6 - 1) = (1, 7, 5)

So there are indeed no such scalars <em>c₁</em>, <em>c₂</em>, and <em>c₃</em>.

5 0
3 years ago
A young oak tree is planted when it is 5 cm tall. It grows 3 cm every month. Write an equation to describe its growth
Naily [24]

Answer:

y=3x+5

Since it's already 5 cm we have +5

every month it would go up by 3 cm so we have 3 and x is to represent the # of months.

8 0
3 years ago
Guys please can you help with this question i dont get it at all. 10 x (-8)
trapecia [35]

Answer:

80 maybe no ummm udk sorry I might

Step-by-step explanation:

I got you I think

4 0
2 years ago
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