The nth taylor polynomial for the given function is
P₄(x) = ln5 + 1/5 (x-5) - 1/25*2! (x-5)² + 2/125*3! (x-5)³ - 6/625*4! (x - 5)⁴
Given:
f(x) = ln(x)
n = 4
c = 3
nth Taylor polynomial for the function, centered at c
The Taylor series for f(x) = ln x centered at 5 is:

Since, c = 5 so,

Now
f(5) = ln 5
f'(x) = 1/x ⇒ f'(5) = 1/5
f''(x) = -1/x² ⇒ f''(5) = -1/5² = -1/25
f'''(x) = 2/x³ ⇒ f'''(5) = 2/5³ = 2/125
f''''(x) = -6/x⁴ ⇒ f (5) = -6/5⁴ = -6/625
So Taylor polynomial for n = 4 is:
P₄(x) = ln5 + 1/5 (x-5) - 1/25*2! (x-5)² + 2/125*3! (x-5)³ - 6/625*4! (x - 5)⁴
Hence,
The nth taylor polynomial for the given function is
P₄(x) = ln5 + 1/5 (x-5) - 1/25*2! (x-5)² + 2/125*3! (x-5)³ - 6/625*4! (x - 5)⁴
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Answer:
16.91176471
Step-by-step explanation:
1725÷102
= 16.91176471
Answer:
x= - 3.5
y= - 6.5
Step-by-step explanation:
-3x+y = 4 equation 1
-9x + 5y = -1 equation 2
and
equation 1 can be written as
y = 4+ 3x
so put this in equation 2
-9x + 5 ( 4+ 3x) = -1
-9x +20 +15x = -1
6x = -21
X= -21 ÷ 6
X = - 3.5
so put this value of x in equation 1 to find value of y
-3 ( -3.5) + y = 4
10.5 + y = 4
y = 4 - 10.5
Y = - 6.5
The answer for this question is going to be: Both x is positive and y is negative.