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3 years ago

-5,15,-45,135 common ratio

Mathematics

1 answer:

S_A_V [24]3 years ago

7 0

Answer:

5 is the common ratio for your numbers

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Which equation is the inverse of y = 16x2 + 1?

Llana [10]

Answer:

$y=\frac{\sqrt{x-1} }{4}$

Step-by-step explanation:

The given equation is

$y=16x^2+1$

For this function to have an inverse, we must restrict the domain, say $x\ge0$

We interchange x and y to get,

$x=16y^2+1$

We now make y the subject to get;

$x-1=16y^2$

We divide through by 16 to get;

$\frac{x-1}{16}=y^2$

We now take the square root of both sides to get;

$\pm \sqrt{\frac{x-1}{16}}=y$

$y=\pm \frac{\sqrt{x-1} }{4}$

Since $x\ge 0$ , the inverse function is

$y=\frac{\sqrt{x-1} }{4}$

6 0

4 years ago

Mickey keeps picking playing cards out of a standard deck of 52 cards, hoping that she will

andrew-mc [135]

Answer:

03%

Step-by-step explanation:

In this situation Mickey should have drew first 7 cards that are not diamond and then on the 8th attempt she should draw an ace.

Let A be the event of drawing 7 cards which are not diamond and B the event of drawing an ace card. therefore required probability is P(A∩B)=P(A)*P(B)

Now, there are 13 diamonds and 39 other cards. Hence,

P(A)=( $\frac{39}{52}$ )⁷=0.1335

After drawing 7 non-diamond cards, the 8th card must be a diamond.Hence,

P(B)= $\frac{13}{52}$ =0.25

Hence, P(A∩B)=P(A)*P(B)=0.1335*0.25=0.033(approximately 0.03,i.e. 3%)

Therefore probability that Mickey will draw her first diamond on the 8th

attempt is 3%

7 0

3 years ago

Match each quadratic function to its graph.

Ede4ka [16]

Answer:

You have to have the graph to answer it.

Step-by-step explanation:

6 0

4 years ago

I really need this answer to be correct

Fed [463]

It is unchanged because the same number would still be in the middle and there would still be the same amount of numbers

if
11,15,21,22,23,27,30 before 22 is the median

if
11,15,21,22,23,27,30 after 22 is still the median

The median is unchanged

4 0

4 years ago

Many companies "grade on a bell curve" to compare the performance of their managers and professional workers. This forces the us

GarryVolchara [31]

Answer:

option A

Step-by-step explanation:

given,

10% A grades 80% B grades 10% C grades

This year, managers with scores less than 35 received C's and those with scores above 425 received A's.

The mean has to be middle of two corresponding cutoff value

$\mu = \dfrac{35+425}{2}$