Solve for slope first:
m =
m =
= -3
then solve for b in y = mx + b
8 = -3(-3) + b
b = -1
y = -3x - 1
m =
m =
then solve for b in y = mx + b
8 = -3(-3) + b
b = -1
y = -3x - 1
In ΔNOP, p = 38 cm, n = 13 cm and ∠O=152°. Find the area of ΔNOP, to the nearest square centimeter.
1 answer:
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Answer: see proof below
<u>Step-by-step explanation:</u>
Given: cos 330 =
Use the Double-Angle Identity: cos 2A = 2 cos² A - 1
Proof LHS → RHS:
LHS cos 165
Double-Angle: cos (2 · 165) = 2 cos² 165 - 1
⇒ cos 330 = 2 cos² 165 - 1
⇒ 2 cos² 165 = cos 330 + 1
Given:
Divide by 2:
Square root:
Scratchwork:
Since cos 165 is in the 2nd Quadrant, the sign is NEGATIVE
LHS = RHS
