Answer:
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In ΔNOP, p = 38 cm, n = 13 cm and ∠O=152°. Find the area of ΔNOP, to the nearest square centimeter.
1 answer:
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Answer:
Step-by-step explanation:
we know that
The lateral area of the cone is equal to
where
r is the radius of the base
l is the slant height
we have
Applying the Pythagoras Theorem find the slant height
substitute in the formula
Define unit vectors along the x-axis and the y-axis as 
respectively.
Then the vector from P to Q is
In component form, the vector PQ is (-8,5).
The magnitude of vector PQ is
√[(-8)² + 5²] = √(89) = 9.434
Answer:
The vector PQ is (-8, 5) and its magnitude is √89 (or 9.434).
Then the vector from P to Q is
In component form, the vector PQ is (-8,5).
The magnitude of vector PQ is
√[(-8)² + 5²] = √(89) = 9.434
Answer:
The vector PQ is (-8, 5) and its magnitude is √89 (or 9.434).