Answer:
#include <stdio.h>
#include <stdlib.h>
int main()
{
char num1[20],num2[20],num3[20],num4[20];
//Checks where the conversion of string to long stops and is required by strtol
char *ptr;
//Stores the converted number string into long.
long result_num1,result_num2,result_num3,result_num4;
//Prompt to enter all the four hexadecimal numbers.
printf("Enter the first hexadecimal number: ");
scanf("%s",num1);
printf("Enter the second hexadecimal number: ");
scanf("%s",num2);
printf("Enter the third hexadecimal number: ");
scanf("%s",num3);
printf("Enter the fourth hexadecimal number: ");
scanf("%s",num4);
//Converting the hexadecimal numbers into long using strtol() function with base 16 for hexadecimal.
result_num1 = strtol(num1,&ptr,16);
result_num2 = strtol(num2,&ptr,16);
result_num3 = strtol(num3,&ptr,16);
result_num4 = strtol(num4,&ptr,16);
//Casting the long to unsigned chars.
unsigned char numb1 = (unsigned char)result_num1;
unsigned char numb2 = (unsigned char)result_num2;
unsigned char numb3 = (unsigned char)result_num3;
unsigned char numb4 = (unsigned char)result_num4;
//Applying the boolean operation on unsigned chars and storing the resultant value in result.
unsigned char result = ((numb1&numb2)|numb3)^numb4;
//Printing the result in capital hex ("%X" take care of this).
printf("%X",result);
return 0;
}
Code OUTPUT
Enter the first hexadecimal number: 1 Enter the second hexadecimal number:2
Enter the third hexadecimal number: 3 Enter the fourth hexadecimal number: 4 Resultant Value: 7 Process returned o (0×0) execution time : 3.076 s
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