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2 years ago

What is 3 1/5 times 1/6?

Mathematics

2 answers:

const2013 [10]2 years ago

8 0

Answer:

0.53333...

Step-by-step explanation:

uysha [10]2 years ago

6 0

Answer:

0.53333333 or 0.54

Step-by-step explanation:

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Round 1.0334 to the nearest thousandth

Tanzania [10]

1.033 is the correct answer

4 0

3 years ago

For each of the figures, write Absolute Value in the form |x-c|=d, where c and d are some numbers, to satisfy the solution set.

Vadim26 [7]

Answer:

$(a)$ $|0 - 8| = 8$

$(b)$ $|-4 - 6| = 10$

Step-by-step explanation:

Given

Attached number lines

Required

Express as: $|x - c| =d$

The two points on the number line represent x and c (in no particular) respectively.

Solving (a):

Let:

$x = 0$

$c = 8$

So:

$|x - c| =d$

$d =|0 - 8|$

Solve the expression in the absolute bracket

$d =|- 8|$

Remove absolute bracket

$d = 8$

So: the expression is;

$|0 - 8| = 8$

Solving (b):

Let:

$x = -4$

$c = 6$

So:

$|x - c| =d$

$d = |-4-6|$

Solve the expression in the absolute bracket

$d = |-10|$

Remove absolute bracket

$d = 10$

So: the expression is;

$|-4 - 6| = 10$

8 0

3 years ago

True or false? the graph represents a function

soldier1979 [14.2K]

Answer:

The graph represents a function...

true

Hope this helps!!

7 0

3 years ago

Let T: set of real numbers R Superscript nℝnright arrow→set of real numbers R Superscript mℝm be a linear transformation, and

Klio2033 [76]

Answer:

$\{T(v_1), T(v_2), T(v_3)\}$ is linearly dependent set.

Step-by-step explanation:

Given: $\{v_1,v_2,v_3\}$ is a linearly dependent set in set of real numbers R

To show: the set $\{T(v_1), T(v_2), T(v_3)\}$ is linearly dependent.

Solution:

If $\{v_1,v_2,v_3,...,v_n\}$ is a set of linearly dependent vectors then there exists atleast one $k_i:i=1,2,3,...,n$ such that $k_1v_1+k_2v_2+k_3v_3+...+k_nv_n=0$

Consider $k_1T(v_1)+k_2T(v_2)+k_3T(v_3)=0$

A linear transformation T: U→V satisfies the following properties:

1. $T(u_1+u_2)=T(u_1)+T(u_2)$

2. $T(au)=aT(u)$

Here, $u,u_1,u_2$ ∈ U

As T is a linear transformation,

$k_1T(v_1)+k_2T(v_2)+k_3T(v_3)=0\\T(k_1v_1)+T(k_2v_2)+T(k_3v_3)=0\\T(k_1v_1+k_2v_2+k_3v_3)=0\\$

As $\{v_1,v_2,v_3\}$ is a linearly dependent set,

$k_1v_1+k_2v_2+k_3v_3=0$ for some $k_i\neq 0:i=1,2,3$

So, for some $k_i\neq 0:i=1,2,3$

$k_1T(v_1)+k_2T(v_2)+k_3T(v_3)=0$

Therefore, set $\{T(v_1), T(v_2), T(v_3)\}$ is linearly dependent.

6 0

3 years ago

A VENDOR SOLD 64 HOTDOGS AT A FOOT BALL GAME.IF THE RATIO OF HOTDOGS TO HAMBURGERS SOLD WAS 8:1 HOW MANY HAMBURGERS DID THE VEND

Vanyuwa [196]

I think 8 hamburgers is the answer.

6 0

3 years ago

Read 2 more answers