Answer:
Mass = 114.26 g
Explanation:
Given data:
Number of gold atoms = 3.47×10²³ atoms
Mass in gram = ?
Solution:
The given problem will solve by using Avogadro number.
It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance. The number 6.022 × 10²³ is called Avogadro number.
1 mole = 6.022 × 10²³ atoms
3.47×10²³ atoms × 1 mol /6.022 × 10²³ atoms
0.58 mol
Mass of gold:
Mass = number of moles × molar mass
Mass = 0.58 mol × 197 g/mol
Mass = 114.26 g
There is too much light entering her eyes.
Answer C is for kg and but it's .00134 for grams
Here we apply the Clausius-Clapeyron equation:
ln(P₁/P₂) = ΔH/R x (1/T₂ - 1/T₁)
The normal vapor pressure is 4.24 kPa (P₁)
The boiling point at this pressure is 293 K (P₂)
The heat of vaporization is 39.9 kJ/mol (ΔH)
We need to find the vapor pressure (P₂) at the given temperature 355.3 K (T₂)
ln(4.24/P₂) = 39.9/0.008314 x (1/355.3 - 1/293)
P₂ = 101.2 kPa
Well, we need to find the ratio of Al to the other reactant.
Al:HCl = 1:3
--> this means that for every 1 Al used, you have to use 3 HCl.
5*3 = 15 moles of HCl needed to fully react with 5 moles of Al. Since 13<15, HCL is the limiting reactant.
The ratio of HCl:AlCl = 3:1
13/3 = 4.3333...
The final answer is HCl is the limiting reactant with 4.3 moles of AlCl3 able to be produced so choice B.
Hope this helps!!! :)
