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2 years ago

Hydrocarbons are separated from each other by a process called cracking distillation.

2 answers:

7 0

True, cracking distillation is one process used to break hydrocarbons into smaller and more useful parts. This is achieved by using high temperatures and pressures with a catalyst. The most common catalyst used are the zeolites.

yan [13]2 years ago

4 0

Answer:

Correct answer is FALSE I just tested it and it came out right.

Explanation:

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A weak monoprotic acid is titrated with 0.100 MNaOH. It requires 50.0 mL of the NaOH solution to reach the equivalence point. Af

larisa86 [58]

Explanation:

The given reaction is as follows.

$HA(aq) + NaOH (aq) \rightleftharpoons NaA(aq) + H_{2}O(l)$

Hence, number of moles of NaOH are as follows.

n = $0.05 L \times 0.1 M$

= 0.005 mol

After the addition of 25 ml of base, the pH of a solution is 3.62. Hence, moles of NaOH is 25 ml base are as follows.

n = $0.025 L \times 0.1 M$

= 0.0025 mol

According to ICE table,

$HA(aq) + NaOH (aq) \rightleftharpoons NaA(aq) + H_{2}O(l)$

Initial: 0.005 mol 0.0025 mol 0 0

Change: -0.0025 mol -0.0025 mol +0.0025 mol

Equibm: 0.0025 mol 0 0.0025 mol

Hence, concentrations of HA and NaA are calculated as follows.

[HA] = $\frac{0.0025 mol}{V}$

[NaA] = $\frac{0.0025 mol}{V}$

$[A^{-}] = [NaA] = \frac{0.0025 mol}{V}$

Now, we will calculate the $pK_{a}$ value as follows.

pH = $pK_{a} + log \frac{A^{-}}{HA}$

$pK_{a} = pH - log \frac{[A^{-}]}{[HA]}$

= $3.42 - log \frac{\frac{0.0025 mol}{V}}{\frac{0.0025}{V}}$

= 3.42

Thus, we can conclude that $pK_{a}$ of the weak acid is 3.42.

8 0

2 years ago

Convert 2.39 x 1022 molecules of water into moles of water

torisob [31]

Answer:

$0.0397\ \text{mol}$

Explanation:

Number of molecules of water = $2.39\times 10^{22}$

$N_A$ = Avogadro's number = $6.022\times 10^{23}\ \text{mol}^{-1}$

Number of moles is given by

$\dfrac{2.39\times 10^{22}}{6.022\times 10^{23}}$

$=0.0397\ \text{mol}$

The number of moles of water is $0.0397\ \text{mol}$ .

6 0

2 years ago

An ionic bond is _?_

lubasha [3.4K]

It would be C, because Ionic bonds have to deal with valence electrons ( the outer shell ones)

8 0

3 years ago

9. At equilibrium a 2 L vessel contains 0.360

klio [65]

Answer:

Ke = 34570.707

Explanation:

H2(g) + Br2(g) → 2 HBr(g)

equilibrium constant (Ke):

⇒ Ke = [HBr]² / [Br2] [H2]

∴ [HBr] = (37.0 mol) / (2 L) = 18.5 mol/L

∴ [Br2] = (0.110 mol) / (2 L) = 0.055 mol/L

∴ [H2] = (0.360 mol) / (2 L) = 0.18 mol/L

⇒ Ke = (18.5 mol/L)² / (0.055 mol/L)(0.18 mol/L)

⇒ Ke = 34570.707

3 0

3 years ago

What is the pH of a solution made by mixing 200 mL of 0.025M HCl and 150 mL of 0.050 M HCl?

seraphim [82]

Answer:

The answer to your question is pH = 1.45

Explanation:

Data

pH = ?

Volume 1 = 200 ml

[HCl] 1 = 0.025 M

Volume 2 = 150 ml

[HCl] 2 = 0.050 M

Process

1.- Calculate the number of moles of each solution

Solution 1

Molarity = moles / volume

-Solve for moles

moles = 0.025 x 0.2

result

moles = 0.005

Solution 2

moles = 0.050 x 0.15

-result

moles = 0.0075

2.- Sum up the number of moles

Total moles = 0.005 + 0.0075

= 0.0125

3.- Sum up the volume

total volume = 200 + 150

350 ml or 0.35 l

4.- Calculate the final concentration

Molarity = 0.0125 / 0.35

= 0.0357

5.- Calculate the pH

pH = -log [H⁺]

-Substitution

pH = -log[0.0357]

-Result

pH = 1.45

8 0

3 years ago