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Schach [20]
3 years ago
6

Chlorine has seven electrons in its valence shell. It accepts an electron to complete its octet and becomes a chlorine ion (Cl-)

. What is the nature of this chlorine ion?
a. Cation
b. Anion
c. Metal ion
Chemistry
1 answer:
Lady_Fox [76]3 years ago
5 0
It becomes an anion because it has a negative charge.
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1. In general, the nucleus of a small atom is stable. Therefore, over very short distances, such as those in a small nucleus,
postnew [5]
<h3>1. <u>Answer;</u></h3>

a. the strong nuclear force is much greater than the electric force.

<h3><u>Explanation</u>;</h3>
  • <em><u>For an atom to be stable it means it has enough amount of binding energy to hold its nucleus together permanently. </u></em>
  • Therefore, <em><u>an unstable atom lacks enough amount of binding energy to hold its nucleus permanently and thus undergoes decay to achieve stability. Unstable atoms are therefore referred to being radioactive.</u></em>
  • Small atoms are stable; <u>this is because they have equal number of protons and neutrons and thus the protons and neutrons fill up energy levels while maximizing the strong force binding the nucleus together. </u>

<h3>9.<u> Answer;</u></h3>

b. change into a different element altogether.

Uranium-238 undergoes alpha decay. Therefore, uranium-238 will  <em><u>change into a different element altogether</u></em>.

<h3><u> Explanation;</u></h3>
  • Unstable atoms undergo radioactive decay in order to achieve stability of their nucleus.
  • <em><u>Uranium-238 is an example of such atom, which may undergo decay to achieve stability.</u></em>
  • <em><u>Alpha decay is one of the types of decays,</u></em> others being beta decay and gamma decay. <em><u>In alpha decay the radioactive isotope undergoes decay such that its mass number is decreased by four and its atomic number is decreased by two.</u></em>
  • Therefore, <em><u>Uranium-238 undergoes alpha decay to form a different element whose mass number is 234 and atomic number is 90, known as thorium-234. </u></em>
5 0
3 years ago
Read 2 more answers
A 50.0 g sample of scandium, sc, is heated by exposure to 1.50 x 10 3 j. The temperature of the sc is raised by 61.1 o
statuscvo [17]

Given mass of Scandium = 50.0 g

Increase in temperature of the metal when heated = 61.1^{0}C

Heat absorbed by Scandium = 1.50*10^{3}J

The equation showing the relationship between heat, mass, specific heat and temperature change:

Q = m C (deltaT)

Where Q is heat = 1.50*10^{3}J

m is mass = 50.0 g

ΔT = 61.1^{0}C

On plugging in the values and solving for C(specific heat) we get,

1.50*10^{3}J=50.0g(C)(61.1^{0}C)

C = 0.491\frac{J}{g^{0}C }

Specific heat of the metal = 0.491\frac{J}{g^{0}C }

7 0
3 years ago
PLEASE ITS A TEST !!!!!!!! HELPPP!!!!!
loris [4]
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8 0
3 years ago
TIMED
zhannawk [14.2K]
Density = mass/volume
Density = 81g/0.9cm³
Density = 90g/cm³
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6 0
3 years ago
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The diagram show the box for an element in the periodic table . What is the atomic mass of the element shown .
DochEvi [55]

Answer:32.1

Explanation:

8 0
3 years ago
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