Answer:
you should know you dont need help so do it by yourself. if you want the awnser you should know or you just dont pay attention in class.1234567890 is your awnser
Answer:
This is the nearest tenth already.
![\bf \textit{surface area of a cylinder}\\\\ SA=2\pi r(h+r)~~ \begin{cases} r=radius\\ h=height\\[-0.5em] \hrulefill\\ r=13.5\\ h=90 \end{cases}\implies SA=2\pi (13.5)(90+13.5) \\\\\\ SA=27\pi (103.5)\implies SA=2794.5\pi \implies SA\approx 8779.18](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Bsurface%20area%20of%20a%20cylinder%7D%5C%5C%5C%5C%20SA%3D2%5Cpi%20r%28h%2Br%29~~%20%5Cbegin%7Bcases%7D%20r%3Dradius%5C%5C%20h%3Dheight%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20r%3D13.5%5C%5C%20h%3D90%20%5Cend%7Bcases%7D%5Cimplies%20SA%3D2%5Cpi%20%2813.5%29%2890%2B13.5%29%20%5C%5C%5C%5C%5C%5C%20SA%3D27%5Cpi%20%28103.5%29%5Cimplies%20SA%3D2794.5%5Cpi%20%5Cimplies%20SA%5Capprox%208779.18)
well, the last part will be with a calculator, but you can simply use the area in π terms.