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3 years ago

8

Juan builds a square dog pen that has an area of 100 square feet. He then builds a second pen that has an area of 49 square feet

. Which is the closest to the percent of the decrease in the area of the pen? *
IT IS NOT 221

2 answers:

Gekata [30.6K]3 years ago

7 0

51..............................................

EleoNora [17]3 years ago

4 0

Answer:

51%

Step-by-step explanation:

Simple. 100-49=51

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The answer for (a) is 28 and the answer for (b) is 13 but I don’t know how to get the answer

denis-greek [22]

Answer:

Step-by-step explanation:

If Quan had 15 and Kaden had 3 times as much, then Kaden had 15(3) = 45. If he spent 10 then he had 35 left. The amount of money Quan had after his mom gave him some was 4/5 the amount of Kaden's 35 (let x = the amount of money Quan has after his mom gives him some):

$x=\frac{4}{5}(35)$ 35 divides by the 5 in the denominator 7 times, and 7 times 4 is 28. That's how you get your 28 in part a.

For part b., he started with 15 and ended with 28, so his mom gave him 28-15=13. That's how you get the 13.

8 0

2 years ago

Word Problems : Subtract 18 rupees 9 paise from 75 rupees 80 paise<br><br>Write In Step by Step

AlladinOne [14]

Answer:

Question

Answers

Related Questions

Subtract the following:

A) 18 rupees 9 paise from 75 rupees 80 paise.

B) 49 rupees 79 paise from 123 rupees 68 paise.

Answer

VerifiedVerified

139.5k+ views

17.4k+ likes

Hint: Use decimal concept.

We know that, 1 rupee = 100 paise. We can reframe these questions as follows:

18 rupees 9 paise from 75 rupees 80 paise

18 rupees 9 paise can be represented as 18.09 rupees and 75 rupees 80 paise can be represented as 75.80 rupees. Now, on subtracting we’ll get,

75.80−18.09−−−−−− 57.71

Which means 57 rupees 71 paise

49 rupees 79 paise from 123 rupees 68 paise

49 rupees 79 paise can be represented as 49.79 rupees and 123 rupees 68 paise can be represented as 123.68 rupees. Now, on subtracting we’ll get,

123.68 −49.79−−−−−− 73.89

Which means 73 rupees 89 paise.

Note: We can also perform the subtraction by making all units the same that are paise and then subtract.

5 0

3 years ago

Read 2 more answers

Find all solutions of the equation in the interval [0, 2pi).

lozanna [386]

Answer:

543

Step-by-step explanation:

8 0

3 years ago

Imagine an experiment having three conditions and 20 subjects within each condition. The mean and variances of each condition ar

xxTIMURxx [149]

Answer:

1. Mean square B= 5.32

2. Mean square E= 16.067

3. F= 0.33

4. p-value: 0.28

Step-by-step explanation:

Hello!

You have the information of 3 groups of people.

Group 1

n₁= 20

X[bar]₁= 3.2

S₁²= 14.3

Group 2

n₂= 20

X[bar]₂= 4.2

S₂²= 17.2

Group 3

n₃= 20

X[bar]₃= 7.6

S₃²= 16.7

1. To manually calculate the mean square between the groups you have to calculate the sum of square between conditions and divide it by the degrees of freedom.

Df B= k-1 = 3-1= 2

Sum Square B is:

∑ni(Ÿi - Ÿ..)²

Ÿi= sample mean of sample i ∀ i= 1,2,3

Ÿ..= general mean is the mean that results of all the groups together.

General mean:

Ÿ..= (Ÿ₁ + Ÿ₂ + Ÿ₃)/ 3 = (3.2+4.2+7.6)/3 = 5

Sum Square B (Ÿ₁ - Ÿ..)² + (Ÿ₂ - Ÿ..)² + (Ÿ₃ - Ÿ..)²= (3.2 - 5)² + (4.2 - 5)² + (7.6 - 5)²= 10.64

Mean square B= Sum Square B/Df B= 10.64/2= 5.32

2. The mean square error (MSE) is the estimation of the variance error (σ $_{e}^2$ → $S_{e} ^{2}$ ), you have to use the following formula:

Se²=<u> (n₁-1)S₁² + -(n₂-1)S₂² + (n₃-1)S₃²</u>

n₁+n₂+n₃-k

Se²=<u> 19*14.3 + 19*17.2 + 19*16.7 </u>= <u> 915.8 </u> = 16.067

20+20+20-3 57

DfE= N-k = 60-3= 57

3. To calculate the value of the statistic you have to divide the MSB by MSE

$F= \frac{Mean square B}{Mean square E} = \frac{5.32}{16.067} = 0.33$

4. P(F $_{2; 57}$ ≤ F) = P(F $_{2; 57}$ ≤ 0.33) = 0.28

I hope you have a SUPER day!

3 0

3 years ago

<img src="https://tex.z-dn.net/?f=%20-%203%20%2B%205i%20%20%5Cdiv%20%20-%203%20-%204i" id="TexFormula1" title=" - 3 + 5i \div

Likurg_2 [28]

Answer:

$\frac{-11}{25}+\frac{-27}{25}i$ given you are asked to simplify

$\frac{-3+5i}{-3-4i}$

Step-by-step explanation:

You have to multiply the numerator and denominator by the denominator's conjugate.

The conjugate of a+bi is a-bi.

When you multiply conjugates, you just have to multiply first and last.

(a+bi)(a-bi)

a^2-abi+abi-b^2i^2

a^2+0 -b^2(-1)

a^2+-b^2(-1)

a^2+b^2

See no need to use the whole foil method; the middle terms cancel.

So we are multiplying top and bottom of your fraction by (-3+4i):

$\frac{-3+5i}{-3-4i} \cdot \frac{-3+4i}{-3+4i}=\frac{(-3+5i)(-3-4i)}{(-3-4i)(-3+4i)}$

So you will have to use the complete foil method for the numerator. Let's do that:

(-3+5i)(-3+4i)

First: (-3)(-3)=9

Outer:: (-3)(4i)=-12i

Inner: (5i)(-3)=-15i

Last: (5i)(4i)=20i^2=20(-1)=-20

--------------------------------------------Combine like terms:

9-20-12i-15i

Simplify:

-11-27i

Now the bottom (-3-4i)(-3+4i):

F(OI)L (we are skipping OI)

First:-3(-3)=9

Last: -4i(4i)=-16i^2=-16(-1)=16

---------------------------------------------Combine like terms:

9+16=25

So our answer is $\frac{-11-27i}{25}{/tex] unless you want to seprate the fraction too:[tex]\frac{-11}{25}+\frac{-27}{25}i$

6 0

3 years ago