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sasho [114]
3 years ago
14

Radio stations use electromagnetic waves for broadcasting. The chart shows different frequencies of waves used by radio stations

. A 2 column by 5 row table. Column 1 is titled Radio Station and contains the following entries: W, X, Y, Z. Column 2 is titled Frequency (Megahertz) and contains the following entries: 88, 95, 90, 99. Which radio station has the wave with the longest wavelength? W X Y Z
Mathematics
2 answers:
Alchen [17]3 years ago
5 0

Answer:

its w or A

Step-by-step explanation:

correct on edge 2021

Neko [114]3 years ago
4 0

Answer:

its d

Step-by-step explanation:

just took the test

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How do u put 3 6/60 as a decimal?
pochemuha
3 over 1 + 6 over 60

[3 over 1 × 60 over 60] + 6 over 60

180 over 60 + 6 over 60 ➡ 186 over 60

186 over 60 ➡ 31 over 10

Then we divide 31 from 10 which give you the quotient of 3.1..


(((Meaning ➡ '"3.1" would be your answer)))


6 0
3 years ago
Stacy and Neil painted 280 ft2 of their living room wall with 45 gallon of paint. How many square feet can they paint with 3 gal
Alecsey [184]

Answer:

They can paint 18. 66 sq ft with 3 gallons of paint.

Step-by-step explanation:

Total area painted = 280 sq ft

Total gallons of paint used = 45

So, 45 gallons of paint painted 280 sq ft.

⇒ By UNITARY METHOD,

1 gallon of paint paints (\frac{280}{45} ) sq ft

So, area painted by 1 gallon = 6.22 sq ft

⇒ area painted by 3 gallon = 6.22 sq ft x 3 = 18. 66 sq ft

So, they can paint 18. 66 sq ft with 3 gallons of paint.

4 0
4 years ago
Which of the following are remote interior angles of 1? Check all that apply.
liraira [26]

Answer:

A. <2

B. <3

Step-by-step explanation:

The remote interior angles are just the two angles that are inside the triangle and opposite from the exterior angle

Remote interior angles of <1 are <2 and <3

3 0
3 years ago
Read 2 more answers
Cal is measuring temperature changes in four substances over different time periods as part of a school project. Which data show
djyliett [7]

Answer:

C) The third table. K= 5

C)\frac{10}{2}=\frac{15}{3}=\frac{25}{5}=\frac{40}{8}=k= 5

Step-by-step explanation:

1) Below there are the missing data:

A proportional relationship through a constant k. It is obtained when we divide:

k=\frac{y}{x}

2)In this case, when we divide the temperature (T) by the time (h).

k=\frac{T}{h}

3)So, examining the table below we are searching for a ratio k common to all measures (temperatures over hour).

A) \frac{12}{3}\neq\frac{25}{5}\neq\frac{36}{6}\neq\frac{81}{9}\\B) \frac{22.5}{3}\neq\frac{30}{4}\neq\frac{52.5}{7}\neq\frac{67.5}{8}\\C)\frac{10}{2}=\frac{15}{3}=\frac{25}{5}=\frac{40}{8}=k= 5\\D)\frac{8.5}{2}\neq\frac{22.5}{5}\neq\frac{28.5}{7}\neq\frac{36}{8}

3 0
3 years ago
Construct a​ 99% confidence interval for the population​ mean, mu. Assume the population has a normal distribution. A group of 1
Zarrin [17]

Answer:

99% confidence interval for the population​ mean is [19.891 , 24.909].

Step-by-step explanation:

We are given that a group of 19 randomly selected students has a mean age of 22.4 years with a standard deviation of 3.8 years.

Assuming the population has a normal distribution.

Firstly, the pivotal quantity for 99% confidence interval for the population​ mean is given by;

         P.Q. = \frac{\bar X - \mu}{\frac{s}{\sqrt{n} } } ~ t_n_-_1

where, \bar X = sample mean age of selected students = 22.4 years

             s = sample standard deviation = 3.8 years

             n = sample of students = 19

             \mu = population mean

<em>Here for constructing 99% confidence interval we have used t statistics because we don't know about population standard deviation.</em>

So, 99% confidence interval for the population​ mean, \mu is ;

P(-2.878 < t_1_8 < 2.878) = 0.99  {As the critical value of t at 18 degree of

                                                freedom are -2.878 & 2.878 with P = 0.5%}

P(-2.878 < \frac{\bar X - \mu}{\frac{s}{\sqrt{n} } } < 2.878) = 0.99

P( -2.878 \times {\frac{s}{\sqrt{n} } } < {\bar X - \mu} < 2.878 \times {\frac{s}{\sqrt{n} } } ) = 0.99

P( \bar X -2.878 \times {\frac{s}{\sqrt{n} } < \mu < \bar X +2.878 \times {\frac{s}{\sqrt{n} } ) = 0.99

<u>99% confidence interval for</u> \mu = [ \bar X -2.878 \times {\frac{s}{\sqrt{n} } , \bar X +2.878 \times {\frac{s}{\sqrt{n} } ]

                                                 = [ 22.4 -2.878 \times {\frac{3.8}{\sqrt{19} } , 22.4 +2.878 \times {\frac{3.8}{\sqrt{19} } ]

                                                 = [19.891 , 24.909]

Therefore, 99% confidence interval for the population​ mean is [19.891 , 24.909].

6 0
3 years ago
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