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3 years ago

I need help with the code practice 9.2 Edhesive. Thank you

Computers and Technology

2 answers:

Natasha_Volkova [10]3 years ago

5 0

Answer:

height = []

height.append([16,17,14])

height.append([17,18,17])

height.append([15,17,14])

print(height)

Explanation: Its correct I got 100%

antiseptic1488 [7]3 years ago

3 0

Answer:

you talking about anaconda navigation? i would love to help!

Explanation:

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What is NOT an issue associated with tag management systems? There is no automation available for tag management systems. Managi

SSSSS [86.1K]

Answer:

Managing tags means experience with the programming language to utilize them.

Explanation:

In different markets, tags are used to assigned prices and values to different products. To make these tags "tag management systems" are deployed to manage and create these tags.

Tag management system is software, that is used to create the tags with ease. There is no need of coding or programming while creating tags.

<em>So we can say that, There is no issue of Managing tags means experience with the programming language to utilize them.</em>

5 0

3 years ago

Read an integer from keyboard and then print the result of the sum obtained by adding the entered integer to the integer formed

Stels [109]

Answer:

Following are the program in C++ language

#include <iostream> // header file

using namespace std; // namespace std;

int main() // main function

{

int number,n1,rem; // variable declaration

int sum,sum1=0;// variable declaration

cout<<"Enter the number :";

cin>>number;// Read the number

n1=number; // initialized the value of number with the n1

while(n1>0) // iteating the while loop

{

rem=n1%10; // finding the reminder

sum1=10*sum1+rem; // storing the sum

n1=n1/10;

}

sum=sum1+number; // calculate the sum

cout<<"The sum is:"<<sum; // Display sum

return 0;

}

Output:

Enter the number :123

The sum is:444

Explanation:

Following are the Description of the Program

Read the value of "number" in the "number" variable of int type .
Initialized the value of "number" in the "n1' variable.
Iterating the while loop until the n1>0.
In this loop we reverse the number in the "sum1" variable
Finally print the sum in the "sum" variable

3 0

3 years ago

. Network navigation devices, such as routers, help datatravel in bundles that are referred toas………..

nataly862011 [7]

Answer: packets

Explanation:

Network navigation devices, such as routers, help data travel in bundles that are referred to as packets. As, networks that transfer the data in small packets are known as packet switching network and that packets carry the data using the internet and the protocol and each of the packet contain some information and data to navigate.

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3 years ago

In today's classrooms, computers are generally being used to

Vinvika [58]

The answer is enhance traditional instruction. Computers are often used by teachers so that the teachers may have an easier time with their visual aids. Now that we have tools like powerpoint presentations and excel files, it will be easier for the teachers to prepare

4 0

3 years ago

[1] Please find all the candidate keys and the primary key (or composite primary key) Candidate Key: _______________________ Pri

AVprozaik [17]

Answer:

Check the explanation

Explanation:

1. The atomic attributes can't be a primary key because the values in the respective attributes should be unique.

So, the size of the primary key should be more than one.

In order to find the candidate key, let the functional dependencies be obtained.

The functional dependencies are :

Emp_ID -> Name, DeptID, Marketing, Salary

Name -> Emp_ID

DeptID -> Emp_ID

Marketing -> Emp_ID

Course_ID -> Course Name

Course_Name -> Course_ID

Date_Completed -> Course_Name

Closure of attribute { Emp_ID, Date_Completed } is { Emp_ID, Date_Completed , Name, DeptID, Marketing, Salary, Course_Name, Course_ID}

Closure of attribute { Name , Date_Completed } is { Name, Date_Completed , Emp_ID , DeptID, Marketing, Salary, Course_Name, Course_ID}

Closure of attribute { DeptID, Date_Completed } is { DeptID, Date_Completed , Emp_ID,, Name, , Marketing, Salary, Course_Name, Course_ID}

Closure of attribute { Marketing, Date_Completed } is { Marketing, Date_Completed , Emp_ID,, Name, DeptID , Salary, Course_Name, Course_ID}.

So, the candidate keys are :

{ Emp_ID, Date_Completed }

{ Name , Date_Completed }

{ DeptID, Date_Completed }

{ Marketing, Date_Completed }

Only one candidate key can be a primary key.

So, the primary key chosen be { Emp_ID, Date_Completed }..

The functional dependencies are :

Emp_ID -> Name, DeptID, Marketing, Salary

Name -> Emp_ID

DeptID -> Emp_ID

Marketing -> Emp_ID

Course_ID -> Course Name

Course_Name -> Course_ID

Date_Completed -> Course_Name

For a relation to be in 2NF, there should be no partial dependencies in the set of functional dependencies.

The first F.D. is

Emp_ID -> Name, DeptID, Marketing, Salary

Here, Emp_ID -> Salary ( decomposition rule ). So, a prime key determining a non-prime key is a partial dependency.

So, a separate table should be made for Emp_ID -> Salary.

The tables are R1(Emp_ID, Name, DeptID, Marketing, Course_ID, Course_Name, Date_Completed)

and R2( Emp_ID , Salary)

The following dependencies violate partial dependency as a prime attribute -> prime attribute :

Name -> Emp_ID

DeptID -> Emp_ID

Marketing -> Emp_ID

The following dependencies violate partial dependency as a non-prime attribute -> non-prime attribute :

Course_ID -> Course Name

Course_Name -> Course_ID

So, no separate tables should be made.

The functional dependency Date_Completed -> Course_Name has a partial dependency as a prime attribute determines a non-prime attribute.

So, a separate table is made.

The final relational schemas that follows 2NF are :

R1(Emp_ID, Name, DeptID, Marketing, Course_ID, Course_Name, Date_Completed)

R2( Emp_ID , Salary)

R3 (Date_Completed, Course_Name, Course_ID)

For a relation to be in 3NF, the functional dependencies should not have any transitive dependencies.

The functional dependencies in R1(Emp_ID, Name, DeptID, Marketing, Date_Completed) is :

Emp_ID -> Name, DeptID, Marketing

This violates the transitive property. So, no table is created.

The functional dependencies in R2 ( Emp_ID , Salary) is :

Emp_ID -> Salary

The functional dependencies in R3 (Date_Completed, Course_Name, Course_ID) are :

Date_Completed -> Course_Name

Course_Name -> Course_ID

Here there is a transitive dependency as a non- prime attribute ( Course_Name ) is determining a non-attribute ( Course_ID ).

So, a separate table is made with the concerned attributes.

The relational schemas which support 3NF re :

R1(Emp_ID, Name, DeptID, Course_ID, Marketing, Date_Completed) with candidate key as Emp_ID.

R2 ( Emp_ID , Salary) with candidate key Emp_ID.

R3 (Date_Completed, Course_Name ) with candidate key Date_Completed.

R4 ( Course_Name, Course_ID ). with candidate keys Course_Name and Course_ID.

6 0

3 years ago