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2 years ago

13

Jen just measured her pet snake and found out it is 51 inches long. The last time she measured, the snake was 34 inches long. Wh

at percent longer Is the pet snake now?

1 answer:

Ilya [14]2 years ago

6 0

Answer:

17 %

Step-by-step explanation:

Just Subtract.

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What is the ‘r’ value of the following sequence: 6, 18, 54, 162…?

goblinko [34]

R = 3
6x3=18
18x3=54
54x3=162 ...

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3 years ago

Identify the slope of the line that passes through the given points (4, 4) and (-2, -3). Identify the slope of the line that pas

bogdanovich [222]

Answer:

m = 7/6

m = -4/9

Step-by-step explanation:

y2 - y1 / x2 - x1

The formula to find the slope.

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2 years ago

35/k = 7/3 what is this answer

miv72 [106K]

Answer:

K=15

Step-by-step explanation:

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2 years ago

Read 2 more answers

The time for this event for boys in secondary school is known to possess a normal distribution with a mean of 460 seconds and a

AlekseyPX

Answer:

The time that the boys need to beat in order to earn a certificate of recognition from the fitness association is 511.264 seconds.

Step-by-step explanation:

We are given that the time for this event for boys in secondary school is known to possess a normal distribution with a mean of 460 seconds and a standard deviation of 40 seconds.

The fitness association wants to recognize the fastest 10% of the boys with certificates of recognition.

<u><em>Let X = time for this event for boys in secondary school</em></u>

SO, X ~ Normal( $\mu=460,\sigma^{2} =40^{2}$ )

The z-score probability distribution for normal distribution is given by;

Z = $\frac{X-\mu}{\sigma}$ ~ N(0,1)

where, $\mu$ = mean time = 460 seconds

$\sigma$ = standard deviation = 40 seconds

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

<u>Now, it is given that the fitness association wants to recognize the fastest 10% of the boys with certificates of recognition, which means;</u>

P(X > x) = 0.10 {where x is the required time which boy need to beat}

P( $\frac{X-\mu}{\sigma}$ > $\frac{x-460}{40}$ ) = 0.10

P(Z > $\frac{x-460}{40}$ ) = 0.10

<em>So, the critical value of x in the z table which represents the top 10% of the area is given as 1.2816, that is;</em>

<em> </em> $\frac{x-460}{40} =1.2816$

${x-460}{} =1.2816\times 40$

<em> </em> $x$ = 460 + 51.264 = <u>511.264 seconds</u>

Hence, the time that the boys need to beat in order to earn a certificate of recognition from the fitness association is 511.264 seconds.

8 0

3 years ago

Lola and Brandon had a running race. They ran 3/10 of a mile. Lola was in the lead for 4/5 of the distance. For what fraction of

Kruka [31]

Answer:

Lola was in lead for $\frac{6}{25}$ of a mile.

Step-by-step explanation:

We have been given that Lola and Brandon had a running race. They ran 3/10 of a mile. Lola was in the lead for 4/5 of the distance.

To find the fraction of a mile for which Lola was in the lead, we need to find 4/5 of 3/10 as:

$\text{Fraction for which Lola was in lead}=\frac{3}{10}\times\frac{4}{5}$

$\text{Fraction for which Lola was in lead}=\frac{3}{5}\times\frac{2}{5}$

$\text{Fraction for which Lola was in lead}=\frac{3\times2}{5\times5}$

$\text{Fraction for which Lola was in lead}=\frac{6}{25}$

Therefore, Lola was in lead for $\frac{6}{25}$ of a mile.

7 0

3 years ago