Answer:
27
Step-by-step explanation:
total=average ×no.
18×40=720 the no. of coins for all children
12×24=288 no. of coins for boys
720-288=432 for all girls
one girl, mean,divide 432 by 16= 27
Step-by-step explanation:
Here
BC=P=10
AC=B=b
AB=H=15
then using fourmula
h^2= p^2+ b^2
b^2= 15×15 - 10× 10
b^2= 125
b=11.2
Answer:
The 38th term of 459,450,441,.. will be:

Step-by-step explanation:
Given the sequence

An arithmetic sequence has a constant difference 'd' and is defined by

computing the differences of all the adjacent terms

so

The first element of the sequence is

so the nth term will be


Putting n=38 to find the 38th term




Therefore, the 38th term of 459,450,441,.. will be:

SOLUTION
Given the question in the image, the following are the solution steps to answer the question.
STEP 1: State the number of outcomes possible for three tossing of a coin
Since a coin has two possible outcomes and is tossed three times, the total outcomes will be:

STEP 2: Find the number of sample spaces for the three tosses
STEP 3: Get the outcomes of the events for which the second toss is tails
Hence, the answers are given as:
Sample Space:

The event that the second toss is tails:
Answer:
19.64$
Step-by-step explanation:
91.89-72.25