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Ludmilka [50]
3 years ago
13

If 600 J of work is done in 3 s, what is the power? (Power: P = W/t) 0.005 W 200 W 603 W 1800 W

Mathematics
2 answers:
nikitadnepr [17]3 years ago
5 0
B) 200W
Hope this helps amigo
Len [333]3 years ago
5 0

Answer:

Option B is correct

the power is, 200 W

Step-by-step explanation:

Using the formula:

\text{Power(P)} = \frac{\text{Work (W)}}{\text{Time(t)}}

As per the statement:

If 600 J of work is done in 3 s

⇒W = 600 J and t = 3 s

then

Using the power formula ;

\text{P} = \frac{\text{W}}{\text{t}}

Substitute the given values we have

\text{P} = \frac{600}{3}=200 J/s

Since, 1 watt(W)= j/s

\text{P} =200 W

Therefore, the power is, 200 W

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Answer:

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Step-by-step explanation:

I don't know if that's the answer you're looking for but have a nice day

8 0
3 years ago
What is the solution of 3x+y=70 and x+y=44 using elimination
Mkey [24]

Answer: y = 31 and x = 13

Step-by-step explanation: Look at the image from the top left to top right, then to bottom right to bottom left.

4 0
2 years ago
What way of solving systems would you Ik use for these two equations ? X=3 y=2x+1
hammer [34]

Answer:

Substitution

Step-by-step explanation:

Subtitue x=3 into the second equation

y=2(3)+1

y=6+1

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5 0
3 years ago
Q5: A school sells tickets to a play. Adult tickets are $8 and student tickets are $4. The school
ella [17]

Answer:

40 adult tickets 68 student tickets

Step-by-step explanation:

8a + 4s = 592

4(a + s = 108)

8a + 4s = 592

4a+ 4s = 432            -

------------------------------

4a = 160

a= 40

s = 180-40

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8 0
3 years ago
(1−√(5))×(2−√(5)) <br><img src="https://tex.z-dn.net/?f=%281%20%2B%204%20%5Csqrt%7B10%7D%20%29%282%20-%20%20%5Csqrt%7B10%7D%20%2
Leviafan [203]
To simplify these expressions, you can either use a calculator (which I'm assuming your teacher doesn't want you to do) or FOIL (distribute).

The first one would be:

(1- \sqrt{5}) (2- \sqrt{5}) \newline =(1)(2)+(1)(- \sqrt{5} )+(- \sqrt{5})(2)+(- \sqrt{5})(- \sqrt{5}) \newline =2- \sqrt{5}-2 \sqrt{5}+5 \newline =7-3 \sqrt{5}

The second one would be:

(1+4 \sqrt{10})( 2- \sqrt{10}) \newline =(1)(2)+(1)(- \sqrt{10})+(4 \sqrt{10} )(2)  +(4 \sqrt{10})(- \sqrt{10}) \newline =2-\sqrt{10}+8 \sqrt{10} -40 \newline =-38+7 \sqrt{10}
3 0
3 years ago
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