Find the difference. -7

Need help with this one

noname [10]

Answer:

f(g(x)) = $\frac{x}{7}$ ; g(f(x)) = 7x - 30

Step-by-step explanation:

6 0

2 years ago

Solve for x. Explain the steps taken to find the solution. 3/2 + 3x/5 = 9/2 4x/5

Iteru [2.4K]

Answer:

46

i just got it right

7 0

2 years ago

Pls helppp me with this

Annette [7]

Answer:

15

Step-by-step explanation:

Applying,

The angle bisector theorem of triangle

From the diagram,

Since ΔAMT is an issoceless triangle,

Then,

Line OA divides Line MT into two equal parts.

Therefore,

Line MO = Line OT.............. Equation 1

From the diagram,

Line MO = 4x-1, Line OT = 3x+3

Substitute into equation 1

4x-1 = 3x+3

Collect like terms

4x-3x = 3+1

x = 4.

Therefore,

OT = 3(4)+3

OT = 12+3

OT = 15

7 0

3 years ago

please help me!!!!!!!!!!!!!

yKpoI14uk [10]

Let x be the length of each row.
Denver can plant 3 rows of a certain length with 2 seedlings leftover.
Total number of seeds he has = 3x+2 Denver can plant 4 rows of the same length with 3 seedling spots left empty.
Total number of seeds he has = 4x-3 Using (i) and (ii), we get= 3x+2=4x-3

Isolate variable terms: 2+3=4x-3
Answer= 5=X

5 0

2 years ago

Suppose a local manufacturing company claims their production line has a variance of less than 9.0. A quality control engineer d

Alexxx [7]

Answer:

$\chi^2 =\frac{35-1}{9} 2.12^2 =16.979$

$p_v =P(\chi^2$

If we compare the p value and the significance level provided we see that $p_v$ so on this case we have enough evidence in order to reject the null hypothesis at the significance level provided. And that means that the population variance is significantly lower than 9

Step-by-step explanation:

Notation and previous concepts

A chi-square test is "used to test if the variance of a population is equal to a specified value. This test can be either a two-sided test or a one-sided test. The two-sided version tests against the alternative that the true variance is either less than or greater than the specified value"

$n=35$ represent the sample size

$\alpha=0.01$ represent the confidence level

$s =2.12$ represent the sample deviation obtained

$\sigma_0 =3$ represent the value that we want to test

Null and alternative hypothesis

On this case we want to check if the population variance specification is lower than 9 and the deviation lower than 3, so the system of hypothesis would be:

Null Hypothesis: $\sigma^2 \geq 9$

Alternative hypothesis: $\sigma^2$

Calculate the statistic

For this test we can use the following statistic:

$\chi^2 =\frac{n-1}{\sigma^2_0} s^2$

And this statistic is distributed chi square with n-1 degrees of freedom. We have eveything to replace.

$\chi^2 =\frac{35-1}{9} 2.12^2 =16.979$

Calculate the p value

In order to calculate the p value we need to have in count the degrees of freedom , on this case df= n-1= 35-1=34. And since is a left tailed test the p value would be given by:

$p_v =P(\chi^2$

In order to find the p value we can use the following code in excel:

"=CHISQ.DIST(16.979,34,TRUE)"

Conclusion

If we compare the p value and the significance level provided we see that $p_v$ so on this case we have enough evidence in order to reject the null hypothesis at the significance level provided. And that means that the population variance is significantly lower than 9

6 0

3 years ago

Find the difference. -7 - (-9)