Explanation:
The prefix trans- and its variant tra- mean "across".
A translucent substance allows some light to go "across" it to the other side. Also, think about a transparent substance: it allows light to go "across" it; or a translation, it is a going "across" from one language into another.
Answer:
E = 26.4 ×10⁻²⁷ j
Explanation:
Given data:
Energy of energy =?
Frequency = 4×10⁷ Hz
Solution:
Formula:
E = hf
E = hf
E = 6.6 ×10⁻³⁴ m²Kg/s . 4×10⁷ Hz
Hz = s⁻¹
j = m²Kg/s
²
E = 26.4 ×10⁻²⁷ j.
Ouestion no 10 answer is first and 11 is 3
Answer:
amino groups
Explanation:
The cellular respiration pathways are central in the extraction of energy from all these different molecules. Amino acids, lipids and other carbohydrates can become different intermediates of glycolysis and the citric acid cycle; this allows them to enter the path of cellular respiration through other different doors. Once these molecules enter the pathway, there is no difference due to their origin: they simply continue through the remaining steps and produce NADH, FADH2 and ATP
When you eat proteins, your body has to break them down into amino acids before they can be used by your cells. Most of the time, amino acids are recycled and used to form new proteins, they do not oxidize as fuel.
However, if there are more amino acids than the body needs or if the cells are fasting, some amino acids are degraded for energy purposes by cellular respiration. In order to enter cellular respiration, amino acids must first get rid of their amino group. This step generates ammonia (NH
3) as a waste product, which - in humans and other mammals - is converted to urea and removed from the body through urine.
Answer:
True
Explanation:
Step 1: Find molecular formula of sucrose
C₁₂H₂₂O₁₁
Step 2: Convert moles of oxygen present to grams
1 mol O = 16 g O
11 mol O = 176 g O
Step 3: Find molar mass of sucrose
C - 12.01 g/mol
H - 1.01 g/mol
O - 16.00 g/mol
12.01(12) + 22(1.01) + 11(16.00) = 342.34 g/mol C₁₂H₂₂O₁₁
Step 4: Set up dimensional analysis
Step 5: Multiply/Divide and cancel out units
Grams of C₁₂H₂₂O₁₁ and grams of C₁₂H₂₂O₁₁ cancel out.
We are left with grams Oxygen
176/342.34 = 0.514109 grams Oxygen
