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3 years ago

Help please !!!

Chemistry

2 answers:

nikklg [1K]3 years ago

8 0

I believe the correct answer would be "It has no energy because it is just sitting there."

I hope this helps! :D

jonny [76]3 years ago

6 0

Answer: this is so hard bro

Explanation:

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Type the correct answer in the box.

Murljashka [212]

Answer:

<em>a= In scientific notation</em>

6.96×10⁵ Km

<em>b =In expanded notation</em>

0.00019 mm

Explanation:

Given data:

Radius of sun = 696000 Km

size of bacterial cell = 1.9 ×10⁻⁴ mm

Radius of sun in scientific notation = ?

Size of bacterial cell in expanded notation = ?

Solution:

Radius of sun:

696000 Km

<em>In scientific notation</em>

6.96×10⁵ Km

Size of bacterial cell:

1.9 ×10⁻⁴ mm

<em>In expanded notation</em>

1.9/ 10000 = 0.00019 mm

8 0

3 years ago

For the reaction shown here, 3.5 mola is mixed with 5.9 molb and 2.2 molc. what is the limiting reactant?3a+2b+c→2d

Misha Larkins [42]

<span>For equation A + 3B + 2C ---> 2D, 1 mole of A will produce 2 moles of D 3 moles of B will produce 2 moles of D, so 1 mole of B will produce 2/3 moles of D 2 moles of C will produce 2 moles of D, so 1 mole of C will produce 1 mole of D If only 1 mole of B is present, only 2/3 moles of D can be produced. This is regardless of the number of moles of A and C. B is the limiting reactant and the maximum number of moles of D expected is 2/3.</span>

7 0

3 years ago

What volume of water vapor would be produced from the combustion of 815.74 grams of propane (C3H8) with 1,006.29 grams of oxygen

d1i1m1o1n [39]

3940.2 is the volume of water vapour that would be produced from the combustion of 815.74 grams of propane ( $C_3H_8$ ) with 1,006.29 grams of oxygen gas, under a pressure of 1.05 atm and a temperature of 350. degrees C.

<h3>What is an ideal gas equation?</h3>

The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).

Stoichiometric calculations:

$C_3H_8(g) + 5 O_2(g)$ → $3 CO_2(g) + 4 H_2O(g)$

From the equation of the reaction, the mole ratio of propane to oxygen is 1:5.

Mole of 815.74 grams of propane = $\frac{ 815.74}{44.1 }$

Mole of 815.74 grams of propane = 18.49750567 moles

Mole of 1,006.29 grams of oxygen = $\frac{ 1,006.29}{32 }$

Mole of 1,006.29 grams of oxygen = 31.4465625 moles

Going by the mole ratio, it appears propane is limiting while oxygen is in excess.

From the equation, 1 mole of propane produces 4 moles of water vapour. Thus, the equivalent mole of water vapour will be:

18.49750567 moles x 4 = 73.99 moles.

Using the ideal gas equation:

PV = nRT

v = (73.99 x 0.08206 x 623) ÷ 0.96

v = 3940.2

Hence, 3940.2 is the volume of water vapour that would be produced from the combustion of 815.74 grams of propane ( $C_3H_8$ ) with 1,006.29 grams of oxygen gas, under a pressure of 1.05 atm and a temperature of 350. degrees C.

Learn more about the ideal gas here:

brainly.com/question/27691721

#SPJ1

7 0

2 years ago

Which of the following statements is true about both nuclear fusion and nuclear fission?

creativ13 [48]

The correct answer is A.

B is incorrect because that only applies to nuclear fission.

C is incorrect because it only applies to nuclear fusion.

D is incorrect because energy can be neither created nor destroyed meaning that this statement is physically impossible,

8 0

3 years ago

Read 2 more answers

An electron can be added to halogen atom to force a halide ion with

Lilit [14]

An electron can be added to halogen atom to force a halide ion with 8 valence electrons

An atom can be defined as the smallest part of an element which can take part in a chemical reaction.

However whenever, an electron is added to halogen atom to force a halide ion with 8 different valence electrons

So therefore; an electron can be added to halogen atom to force a halide ion with 8 valence electrons

Learn more about halogens:

brainly.com/question/18276987

#SPJ1

4 0

2 years ago