<span>Air pressure decreases as you move higher in the atmosphere. Think of a column of air directly over your body. ... Just as air pressure decreases with altitude, so does the density of air.</span>
Answer:
Kc = Kc = 8.0 * 10^9
Kp = 5.5 *10^5
Explanation:
Step 1: Data given
Temperature = 25.0 °C
Number of moles Fe = 1.0 moles
Number of moles O2 = 1.0 * 10^-3 moles
Number of moles Fe2O3 = 2.0 moles
Volume = 2.0 L
Step 2: The balanced equation
4Fe(s) + 3O2(g) ⇌ 2Fe2O3(s)
Step 3: Calculate molarity
Molarity = moles / volume
[Fe] = 1.0 moles / 2.0 L
[Fe] = 0.5 M
[O2] = 0.001 moles / 2.0 L
[O2] = 0.0005 M
[Fe2O3] = 2.0 moles / 2.0 L
[Fe2O3] = 1.0 M
Step 4: Calculate Kc
Kc =1/ [O2]³
Kc = 1/0,.000000000125
Kc = 8.0 * 10^9
Step 5: Calculate Kp
Kp = Kc*(R*T)^Δn
⇒with Kc = 8.0*10^9
⇒with R = 0.08206 L*atm /mol*K
⇒with T = 298 K
⇒with Δn = -3
Kp = 8.10^9 *(0.08206 * 298)^-3
Kp = 5.5 *10^5
The volume (in liters) of CO₂ that can be consumed at STP by 435 g Na₂O₂ is 125 L of Co₂
<u><em>calculation</em></u>
2Na₂O₂(s) +2 CO₂ (g)→ 2 Na₂CO₃(s) + O₂(g)
Step 1 : find the moles of Na₂O₂
moles = mass÷ molar mass
from periodic table the molar mass of Na₂O₂ = (23 x2) +( 16 x2) = 78 g/mol
moles= 435 g÷ 78 g/mol = 5.58 moles
Step 2: use the mole ratio to determine the moles of CO₂
from given equation Na₂O₂ : CO₂ =2 :2 =1:1
Therefore the moles of CO₂ is also = 5.58 moles
Step 3: find the volume of CO₂ at STP
that is at STP 1 mole of a gas = 22.4 L
5.58 moles = ? l
<em>by cross multiplication</em>
= (5.58 moles x 22.4 L) / 1 mole = 125 L
If you are doing an experiment with chemicals, you would like to take the initial temperature, then do the experiment. After you do the experiments, you would like to take the temperature again to see if the chemicals made the temperature increase or decrease.
Have a nice day! :)
Answer:
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Explanation:
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