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3 years ago

Pls help me brainliest, rattings etc its 2 questions and I am very confused! 8 pts!

Chemistry

2 answers:

xenn [34]3 years ago

8 0

Question 10 is the decomposition of water. The left side is 2 water molecules, while the right side is two hydrogen molecules and 2 oxygen molecules.

Question 11 consists of calculating the amounts of atoms on each side. Since the left side has 6 hydrogen atoms, the right side must as well. On the right side, hydrogen has a 2. So divide 6 by 2 to find the coefficient (3). You can confirm the answer by confirming the oxygen is the same on both sides (it is).

Serjik [45]3 years ago

6 0

Ouestion no 10 answer is first and 11 is 3

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50 points!! i need 3 answers!!!

tester [92]

Option E, Real gas particles have more complex interactions than ideal gas particles.

In ideal gases, there is absolutely no interaction between any atoms. At all. Atoms simply don't bump into each other in ideal gases.

Obviously, you know that's unrealistic. In real gases, atoms collide into each other all the time.

-T.B.

3 0

3 years ago

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Can I have help with Environmental Science? Explain how a GIS can model the ways that changes in climate can influence human act

Sergeu [11.5K]

Answer:

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3 years ago

Which of these molecules is nonpolar? O A. PF 3 O B. 02 O C. CO O D. CHCI

zloy xaker [14]

B is the answer

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5 0

3 years ago

How many grams in 6.20 x 10^25 atoms of bromine (Br) ? image attached , will give brainliest

Deffense [45]

Answer:

8239.2g

Explanation:

Given parameters:

Number of atoms in Br = 6.2 x 10²⁵atoms

Unknown:

Mass of Br = ?

Solution:

From mole concepts, we know that:

1 mole of a substance contains 6.02 x 10²³ atoms/mol

Molar mass of Br = 80g/mol

6.2 x 10²⁵atoms x $\frac{1}{6.02 x 10^{23} }$ $\frac{mol}{atoms}$ x 80 x $\frac{g}{moles}$

= 8239.2g

8 0

3 years ago

How many atoms are in 10.1 g Ne

LekaFEV [45]

Answer:

3.01 × 10²³ atoms Ne

General Formulas and Concepts:

Atomic Structure

Reading a Periodic Tables
Moles

Stoichiometry

Using Dimensional Analysis

Explanation:

Step 1: Define

Identify

[Given] 10.1 g Ne

[Solve] atoms Ne

Step 2: Identify Conversions

Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

[PT] Molar Mass of Ne: 20.18 g/mol\

Step 3: Convert

[DA] Set up: $\displaystyle 10.1 \ g \ Ne(\frac{1 \ mol \ Ne}{20.18 \ g \ Ne})(\frac{6.022 \cdot 10^{23} \ atoms \ Ne}{1 \ mol \ Ne})$
[DA] Divide/Multiply [Cancel out units]: $\displaystyle 3.01398 \cdot 10^{23} \ atoms \ Ne$

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

3.01398 × 10²³ atoms Ne ≈ 3.01 × 10²³ atoms Ne

4 0

3 years ago