Answer:
The answer to the question is
At an altitude of 1413 km or 1.222·R above the north pole the weight of an object reduced to 67% of its earth-surface value
Explanation:
We make use of the gravitational formula as follows
F = G
where
m₁ = mass of the object
m₂ = mass of the earth
d = distance between the two objects and
G = gravitational constant
if at the altitude the weight is reduced to 67 % of its weight on earth then
with all other variables remaining constant, we have
67% F = G
=0.67× G×
cancelleing like ternss from both sides we have
1/R₂² =0.67/R₁² or r₁²/R₂² =0.67 and R₁/R₂ = 0.8185
or R₂ = R₁/0.8185 or 1.222·R = (6.37×10⁶ m)/0.8185 = 7.783×10⁶ m
Hence at an altitude = 1.413×10⁶ m the weight of the object will reduce to 67% its earth-surface value
Answer:
The normal force of weight will not differ for different placements but the force of pressure applied to the surface of your hand is per unit area. So the side with the smallest area.. 3 cm x 6 cm will exert the most pressure on your hand.
Please Give Brainliest
Answer:
10 Joule
Explanation:
The solution and answer are well written in the Pic above.
Answer:
The Skater's final angular speed =8rad/s
Explanation:
Let initial momentum of inertia be I1
Let final momentum of inertia be I2
But I2= I1/2
It is decreased by one-half
There is no external torque on the system, therefore
I1w1=I2w2
I1×4=(I1/2)×w2
Dividing through by I1 on both sides leaves you with:
4=w2/2
Cross multiply
W2=4×2=8rad/s
Answer:
When you in a airplane you are in high altitude and thats where air density drops. Thats where ear pops come from.
Explanation: