Hey girl
the answer is A
your correct the atmosphere provides warmth
hope this helps
XD
Now for this problem, what is given is a 40 Newtons which would represent the force to be applied to the object, and a distance of 10 meters after the application of the said force. When these two combine, work is done. The unit for work is Joules and this is what we are looking for. The formula to get Joules or for work would be the force applied to the object multiplied by the distance that it travelled after the application of the force. It looks like this
work = force x distance
Joules = Newtons x meter
so let us substitute the variables to their corresponding places
Joules = 40 N x 10 m
Joules = 400 J
So the answer to this question would be C. 400 J
Distance = (speed) x (time)
Distance = (10 meter/second) x (2 minutes)
Distance = (10 meter/second) x (2 minutes) x (60 second/minute)
Distance = (10 x 2 x 60) (meter-minute-second / second-minute)
<em>Distance = 1,200 meters</em>
Answer:
body position 4 is (-1,133, -1.83)
Explanation:
The concept of center of gravity is of great importance since in this all external forces are considered applied, it is defined by
x_cm = 1 /M ∑ 
m_{i}
y_cm = 1 /M ∑ y_{i} mi
Where M is the total mass of the body, mi is the mass of each element
give us the mass and position of this masses
body 1
m1 = 2.00 ka
x1 = 0 me
y1 = 0 me
body 2
m2 = 2.20 kg
x2 = 0m
y2 = 5 m
body 3
m3 = 3.4 kg
x3 = 2.00 m
y3 = 0
body 4
m4 = 6 kg
x4=?
y4=?
mass center position
x_cm = 0
y_cm = 0
let's apply to the equations of the initial part
X axis
M = 2.00 + 2.20 + 3.40
M = 7.6 kg
0 = 1 / 7.6 (2 0 + 2.2 0 + 3.4 2 + 6 x4)
x4 = -6.8 / 6
x4 = -1,133 m
Axis y
0 = 1 / 7.6 (2 0 + 2.20 5 +3.4 0 + 6 y4)
y4 = -11/6
y4 = -1.83 m
body position 4 is (-1,133, -1.83)
Frictional force from the friction caused between the course pavement and the rubber tire. It wears down the tire.
