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san4es73 [151]
4 years ago
6

Kinematics in 1D [4B.R]:Question 3

Physics
1 answer:
Stels [109]4 years ago
6 0

Answer:

Only if the acceleration is uniform

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Kelly sits on a rock. her weight is an action force. describe the reaction force
Lorico [155]
Kelly is pulling on the rock and the earth, but the rock's mass and the earth's mass overpowers her mass, so she is pushed up by the rock and earth.
6 0
4 years ago
The
Finger [1]

Answer:

1.) 10.61 A

2.) 0.27 A

Explanation:

Given that a sinusoidal A.C has a maximum value of 15A.

1) What are its r.m.s values?

ii) If the time is recorded from the instant the current is zero and is becoming

positive, what is the instantaneous value of the current after 1/300s, given the

frequency is 50 Hz.​

Solution.

1.)

The r.m.s current = peak current/root 2

The r.m.s current = 0.7071 × 15

The r.m.s current = 10.61 A

2.)

Given that

Time = 1/300 s

Frequency = 50 Hz

Instantaneous current can be calculated by using the formula

I = I sin wt

Where w = 2πf

Instantaneous current = 15( sin 2πft)

I = 15 × sin ( 2 × 3.143 × 50 × 1/300 )

I = 15 × sin ( 1.047 )

I = 15 × 0.01827

I = 0.27 A

Therefore, the instantaneous current is 0.27A

3 0
3 years ago
A whistle produces sound of frequency of 1.00 kHz. If a listener moves with a speed of 30 m/s away from the whistle, what freque
Serggg [28]

Answer:

The frequency the listener hears is 911.765 Hz.

Explanation:

The speed of a sound is 340 m/s

The speed of listener is 30 m/s in a direction away from the whistle.

The speed of the listener with respect to the sound waves from the whistle

= ( 340 - 30) m/s

= 310 m/s

This because the direction of the sound waves from the whistle and the direction of travel of the listener are the same, that is, both are traveling away from the whistle.

Therefore from the formula we get

⇒     \frac{f_2}{f_1}  = \frac{v_2}{v_1}            ⇒  f_2 = 1000 \times \frac{310}{340}  = 911.765 \hspace{0.1cm} Hz

The frequency the listener hears is 911.765 Hz.

8 0
3 years ago
I shoot a bullet up at 270 m/s. How long does it fly for????
IrinaVladis [17]

Answer:

5 minutes

Explanation:

4 0
3 years ago
A positive charge, q1, of 5 µC is 3 × 10–2 m west of a positive charge, q2, of 2 µC. What is the magnitude and direction of the
EastWind [94]
The law you need is :
lets call the constant c = 4pi*epsilon naught*r2.
where r is radius ( or seperation of the charges). epsilon naught is a constant of about 8.85*10^-12 or something like that. and 4 pi is just 4 times pi.
the actual equation is 
FORCE= (q1*q2)/c

4 0
4 years ago
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