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3 years ago

Which flow diagram BEST explains the energy transformations that occur within an automobile running on diesel?

Physics

2 answers:

faust18 [17]3 years ago

6 0

A chemical energy ➡️Kinetic energy ➡️Heat energy

Lubov Fominskaja [6]3 years ago

3 0

Answer: A) chemical energy → kinetic energy→ heat energy

Explanation:

Energy neither forms nor gets destroyed. Energy gets converted from one form to another. Diesel is a fuel which has chemical energy. When automobile starts running, the engine burns the fuel and it converts into kinetic energy with runs the automobile and the energy is converted to heat.

Hence, the correct sequence of energy transformation would be:

A) chemical energy → kinetic energy→ heat energy

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Two children are pulling on opposite sides of a blanket. The brother is pulling with a force of 3 N. The sister is pulling with

Citrus2011 [14]

Let F1=Force exerted by the brother (+F1)
F1= Force exerted by the sister (-F2)

Fnet=(+F1) + (-F2)
Fnet= (+F1) + (-F2)
Fnet=F1 - F2
Fnet= (+3N)+(-5N)
Fnet= -2N

-F

towards the sister (-F) (greater force applied)

7 0

3 years ago

A cylindrical specimen of some metal alloy having an elastic modulus of 108 GPa and an original cross-sectional diameter of 3.7

kaheart [24]

Answer:

L= 276.4 mm

Explanation:

Given that

E= 180 GPa

d= 3.7 mm

F= 1890 N

ΔL= 0.45 mm

We know that ,elongation due to load F in a cylindrical bar is given as follows

$\Delta L =\dfrac{FL}{AE}$

$L=\dfrac{\Delta L\times AE}{F}$

Now by putting the values in the above equation we get

$L=\dfrac{0.45\times 10^{-3}\times \dfrac{\pi}{4}\times (3.7\times 10^{-3})^2\times 108\times 10^9}{1890}\ m$

L=0.2764 m

L= 276.4 mm

Therefore the length of the specimen will be 276.4 mm

5 0

4 years ago

A planet of mass m moves around the Sun of mass M in an elliptical orbit. The maximum and minimum distance of the planet from th

zzz [600]

Answer:

the relation between the time period of the planet is

T = 2π √[( r1 + r2 )³ / 8GM ]

Explanation:

Given the data i the question;

mass of sun = M

minimum and maximum distance = r1 and r2 respectively

Now, using Kepler's third law,

" the square of period T of any planet is proportional to the cube of average distance "

T² ∝ R³

average distance a = ( r1 + r2 ) / 2

we know that

T² = 4π²a³ / GM

T² = 4π² [( ( r1 + r2 ) / 2 )³ / GM ]

T² = 4π² [( ( r1 + r2 )³ / 8 ) / GM ]

T² = 4π² [( r1 + r2 )³ / 8GM ]

T = √[ 4π² [( r1 + r2 )³ / 8GM ] ]

T = 2π √[( r1 + r2 )³ / 8GM ]

Therefore, the relation between the time period of the planet is

T = 2π √[( r1 + r2 )³ / 8GM ]

5 0

3 years ago

Can anyone help me with this question please

JulsSmile [24]

Explanation:

V=u+at

where,

v=final speed

u=initial speed,(starting speed)

a=acceleration

t=time

v=u+at = 6=2+a*2

6=2+2a

2a=6-2

2a=4

a=4/2 = 2

a =2

2. to find time taken

v=u+at

25=5*2t

2t=25-5

2t=20

t=20/2

t=10sec

3. finding final speed

v=u+at

v=4+10*2

=4+20

v=24m/sec

5.v=u+at

=5+8*10

=5+80

V=85m/sev

6. v=u+at

8=u+4*2

8=u+8

U=8/8

u=1

these are your missing values

5 0

3 years ago

What type on msd causes inflammation of the tendons that correct bones to muscles

svp [43]

I believe it would be Tendonitis

8 0

4 years ago