All categories

4 years ago

What is equivalent to 4.321 × 10−4 ? What is equivalent to 4.321 × 10−4 ?

1 answer:

7 0

Please write that as 4.321 × 10^(−4). The " ^ " indicates exponentiation and the parentheses help make clear that your exponent here is a negative one.

Rewrite 4.321 × 10^(−4) by moving the decimal point 4 places to the left:

0.0004321

You might be interested in

A television network is deciding whether or not to give its newest television show a spot during prime viewing time at night. If

Alinara [238K]

Answer:

Test statistic z= 1.708

Step-by-step explanation:

given that a television network is deciding whether or not to give its newest television show a spot during prime viewing time at night. If this is to happen, it will have to move one of its most viewed shows to another slot.

Sample size n = 827

Sample proportion p = $\frac{438}{827} \\=0.5297$

$H_0: p =0.5\\H_a: p >0.5$

(right tailed test)

This is because they would be interested if more than half viewers are ready for the change

Test statistic = Z = p difference/std error

p difference = 0.0297

Std error = $\sqrt{\frac{pq}{n} } \\=\sqrt{\frac{0.5*0.5}{827} } \\=0.0174$

Z =1.708

p valu e= 0.9562

Since p >0.05 we fail to reject H0

Test statistic z= 1.708

8 0

3 years ago

Show problem set up for full credit.

ICE Princess25 [194]

Answer:

∠ QPR = 125°

Step-by-step explanation:

the angles subtended by 2 congruent arcs are congruent , that is

5x = 4x + 25 ( subtract 4x from both sides )

x = 25

Then

∠ QPR = 4x + 25 = 4(25) + 25 = 100 + 25 = 125°

5 0

2 years ago

In the diagram below, DE is parallel to ty. What is the value of y!

rjkz [21]

Answer: A 80 i hope this helps

Step-by-step explanation:

6 0

3 years ago

Five bells begin to ring together and they ring at intervals of 3, 6, 10, 12 and 15 seconds, respectively. How many times will t

Evgen [1.6K]

Answer:

60 times will they ring together at the same second in one hour excluding the one at the end.

Step-by-step explanation:

Given : Five bells begin to ring together and they ring at intervals of 3, 6, 10, 12 and 15 seconds, respectively.

To find : How many times will they ring together at the same second in one hour excluding the one at the end?

Solution :

First we find the LCM of 3, 6, 10, 12 and 15.

2 | 3 6 10 12 15

2 | 3 3 5 6 15

3 | 3 3 5 3 15

5 | 1 1 5 1 5

| 1 1 1 1 1

$LCM(3, 6, 10, 12,15)=2\times 2\times 3\times 5$

$LCM(3, 6, 10, 12,15)=60$

So, the bells will ring together after every 60 seconds i.e. 1 minutes.

i.e. in 1 minute they rand together 1 time.

We know, 1 hour = 60 minutes

So, in 60 minute they rang together 60 times.

Therefore, 60 times will they ring together at the same second in one hour excluding the one at the end.

6 0

3 years ago

PLEASE HELP I WILL GIVE BRAINLIEST TO RIGHT ANSWERS ONLY

Fofino [41]

Answer:

logb(x y) = y ∙ logb(x)

Step-by-step explanation:

4 0

3 years ago