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Bogdan [553]
3 years ago
6

Find the exact circumference. r = 6 mm, C = ?

Mathematics
1 answer:
Kazeer [188]3 years ago
5 0
C=2 \pi r \\ C=2 \pi 6 \\ C=12 \pi
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What is the distance between the points (21 , 11) and (4 , 11) in the coordinate plane?
k0ka [10]

Answer:

asdasda

Step-by-step explanation:

asasjdafk askfamjscasfkasdmasjd kamdsjakfasjfsakmcfaksaj

5 0
3 years ago
What is the degree of the polynomial?<br> 5x^3<br><br> 0<br> 1<br> 2<br> 3
Trava [24]
I guess it is d: three

4 0
3 years ago
Read 2 more answers
20% of 57 is what number ?<br> The proportion is ?
Elanso [62]

Answer:

11.4

20/100 = x/57

Step-by-step explanation:

It is perhaps simplest just to translate the given English sentence into a mathematical sentence.

... 20% ... ... of ... 57 ... is ... what number

... 20/100 ... × ... 57 .... = ... what number . . . . . . . . translation to math sentence

... 11.4 = what number . . . . . . . . carry out the multiplication

_____

If you're asked to write this as a proportion, you can write it like this:

\dfrac{20}{100}=\dfrac{\text{what number}}{57}

You can solve this proportion by multiplying by 57 (the denominator under "what number"). Doing so gives you the same arithmetic sentence as shown above.

6 0
3 years ago
Lisa, an experience shipping clerk, can fill a certain order in 10 hours. Bill, a new clerk, needs 13 hours to do the same job.
Lelu [443]
I think 11 hours and 30 minutes
7 0
3 years ago
Please help logarithms!
nlexa [21]

Given:

\log_34\approx 1.262

\log_37\approx 1.771

To find:

The value of \log_3\left(\dfrac{4}{49}\right).

Solution:

We have,

\log_34\approx 1.262

\log_37\approx 1.771

Using properties of log, we get

\log_3\left(\dfrac{4}{49}\right)=\log_34-\log_349      \left[\because \log_a\dfrac{m}{n}=\log_am-\log_an\right]

\log_3\left(\dfrac{4}{49}\right)=\log_34-\log_37^2      

\log_3\left(\dfrac{4}{49}\right)=\log_34-2\log_37          [\log x^n=n\log x]

Substitute \log_34\approx 1.262 and \log_37\approx 1.771.

\log_3\left(\dfrac{4}{49}\right)=1.262-2(1.771)

\log_3\left(\dfrac{4}{49}\right)=1.262-3.542

\log_3\left(\dfrac{4}{49}\right)=-2.28

Therefore, the value of \log_3\left(\dfrac{4}{49}\right) is -2.28.

5 0
3 years ago
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